Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan= 5/11.65
=23.23°
AC= km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
B = (- 4, )
Step-by-step explanation:
Using the Section formula
= = = = - 4
= = = =
Thus coordinates of B = (- 4, )
Answer:
1.) y= 3
2.) y = 3/4 x -3
Step-by-step explanation:
Answer:
h(3b)=12b+4
another answer
h(3b)=4(3b+1)
Step-by-step explanation:
h(x)=4x+4
h(3b)=4(3b)+4
h(3b)=12b+4
if need to simplify..then:
h(3b)=4(3b+1)