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sp2606 [1]
3 years ago
13

The area of rectangular is 64m the length of the pool is 12 m less that the width .The situation can be represented by the equat

ion x
Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

Width = 16 m

Length = 4 m

Step-by-step explanation:

The area of rectangular is 64m² the length of the pool is 12 m less that the width . The situation can be represented by the equation x

Area of a rectangle = Length × Width

L = W - 12

Hence:

64 = (W - 12) × W

64 = W² - 12W

W² - 12W - 64 = 0

Factor using

(W + 4)(W - 16) = 0

Width = 16m

Length = W - 12

Length = 16 m - 12 m

= 4 m

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Number 49....I need help
sergiy2304 [10]
Now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.

now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\
-------------------------------\\\\
\begin{cases}
200=F+2x\implies 200-2x=\boxed{F}\\
245=F+8x\\
----------\\
245=\boxed{200-2x}+8x
\end{cases}
\\\\\\
45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby 
\begin{array}{llll}
\textit{so the 25mile charge is}\\
\textit{7 bucks and 50cents}
\end{array}
\\\\\\


\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F
\\\\\\
\textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450}
\\\\\\
\boxed{y=185+\frac{15}{2}x}\qquad 
\begin{cases}
450~miles\\\\
\cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\
x=18
\end{cases}
\\\\\\
y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320
7 0
3 years ago
1. since A^2= 36x^2, a=?<br> 2. since b^2= 49, b=?
Wewaii [24]

Answer:

D

Step-by-step explanation:

36x² - 49 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

then

36x² - 49

= (6x)² - 7²

= (6x - 7)(6x + 7)

Thus 6x - 7 is a factor of the expression

7 0
2 years ago
Read 2 more answers
Please double-check for me :)
frosja888 [35]

<em>I think your answer is fine</em>

8 0
3 years ago
Time sensitive question. Find the sum of the first 26 terms of an arithmetic series whose first term is 7 and 26th term is 93.
lisabon 2012 [21]

ANSWER

S_{26}=1300

EXPLANATION

The sum of an arithmetic sequence whose first term and last terms are known is calculated using

S_{n}= \frac{n}{2} (a + l)

From the given information, the first term of the series is

a = 7

and the last term of the series is

l = 93

The sum of the first 26 terms is

S_{26}= \frac{26}{2} (7 + 93)

S_{26}= 13 (100)

S_{26}=1300

7 0
3 years ago
3t-8 I’m not sure pls help me
densk [106]

Answer: 3t-8

Step-by-step explanation:

<em>3t-8 is the answer because there are no like terms.</em>

<em />

6 0
3 years ago
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