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Whitepunk [10]
2 years ago
6

I need answers!!!!!!!!!

Mathematics
2 answers:
Artist 52 [7]2 years ago
8 0
The answer is the last option!!
GalinKa [24]2 years ago
4 0

Answer:

Reflection figure Q was flipped over the y-axis, the line of reflection.

Step-by-step explanation:

The figures have the same lengths but they are reflected.

Hope this helps! :)

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Factorise fully<br> 8 + 49
Anestetic [448]

Answer: 8 + 49 factored is 57

I hope this helps you

4 0
2 years ago
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Draw the graph of y = 3x - 1<br> on the grid.
Mashcka [7]
Can you send a picture easier to solve
6 0
3 years ago
What is the slope-intercept form of the function described by this table?
Pavel [41]

Answer:

y = -4x +2

Step-by-step explanation:

As x-values increase by 1, y-values decrease by 4. The slope of the line is ...

... m = (change in y)/(change in x) = -4/1 = -4

We can use the first (x, y) pair as a point to use in the point-slope form of the equation of a line. That form can be written, for slope m and point (h, k) ...

... y = m(x -h) +k

using m = -4 and (h, k) = (1, -2), we can fill in the numbers to get ...

... y = -4(x -1) -2

... y = -4x +4 -2 . . . . eliminate parentheses

... y = -4x +2 . . . . . . slope-intercept form

_____

<em>Alternate approach</em>

After you recognize that a change in x of 1 gives a change in y of -4, you can work backward one step to find the table value for y corresponding to x=0. That will be -2+4 = +2. Now, you know both the slope (-4) and the y-intercept (+2), so you can write the equation directly from this knowledge:

... y = -4x +2

7 0
2 years ago
How much is 2 plus 3
levacccp [35]

Answer:

5

Step-by-step explanation:

Add

8 0
2 years ago
Read 2 more answers
An evolutionary biologist examined the relative fitness of Escherichia coli bacteria grown for 2000 generations, about 300 days,
Varvara68 [4.7K]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: fitness of a line of E. coli grown on an acidic environment.

n= 6 E. coli lines

Recorded fitness for each line: 1.24, 1.22, 1.23, 1.24, 1.18, 1.09

The relative fitness of 1 indicates that both bacteria types are equally fit.

A relative fitness larger than 1 indicates that the acid-evolved line is more fit than the parental line kept at neutral pH when both are grown in acidic conditions.

Meaning that if the average fitness of the E. coli lines grown on an acidic environment is greater than 1 then they are better adjusted to live in acidic conditions, symbolically: μ > 1

The statistic hypotheses are:

H₀: μ ≤ 1

H₁: μ > 1

α: 0.05

Assuming that the variable has a normal distribution you have to apply a one-sample t-test:

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}

X[bar]= 1.20

S= 0.06

t_{H_0}= \frac{1.20-1}{\frac{0.06}{\sqrt{6} } } = 8.40

The p-value for this test is 0.0002

Since the p-value= 0.0002 is less than α:0.05 the decision is to reject the null hypothesis.

Then at a 5% significance level, there is significant evidence to conclude that the bacteria evolved in acidic pH are better adapted to acidic conditions.

I hope you have a SUPER day!

7 0
3 years ago
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