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2 years ago

6

I need answers!!!!!!!!!

2 answers:

Artist 52 [7]2 years ago

8 0

The answer is the last option!!

GalinKa [24]2 years ago

4 0

Answer:

Reflection figure Q was flipped over the y-axis, the line of reflection.

Step-by-step explanation:

The figures have the same lengths but they are reflected.

Hope this helps! :)

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2. Find the product of each of the following:

Kruka [31]

Step-by-step explanation:

$i) \: \frac{3}{5} \times ( \frac{ - 7}{8} ) = - \frac{21}{40} \\ \\ ii) \: \frac{ - 9}{2} \times \frac{5}{4} = - \frac{45}{8} \\ \\ iii) \: \frac{ - 6}{11} \times \frac{5}{3} = - \frac{10}{11} \\ \\ iv) \: \frac{ - 2}{3} \times \frac{6}{7} = - \frac{4}{7} \\$

6 0

2 years ago

Does 6(3−5w)=5(4−2w)−20w have one solution, no solution, or infinitely many solutions? <br><br> plzz

Vikki [24]

Answer:

No solutions

Step-by-step explanation:

18-30w=20-10w-20w

18-30w=20-30w

18-20=30w-30w

-2 does not equal to 0

No solutions

6 0

2 years ago

A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa

tatuchka [14]

Answer:

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

$y=x\left(0.15-0.001x\right)$

$y=0.15x-0.001x^2$

To find maximum height of second puck

$y'=0.15-0.002x$

Equate the derivative equals to 0

0.15-0.002x=0

$\frac{0.15}{0.002}=x$

75 = x

At x = 75

$y=0.15(75)-0.001(75)^2=5.625$

So, The maximum height of second puck is greater than first puck

So, Second puck travels farther

5 0

2 years ago

Help please im doing my finals

AysviL [449]

Sorry it to hard to help out next times

8 0

2 years ago

Help needed asap please

Alenkasestr [34]

Answer:

I don't understand the language you used

6 0

2 years ago

Read 2 more answers