X + y = 8
x - y = 12
--------------add
2x = 20
x = 20/2
x = 10
x + y = 8
10 + y = 8
y = 8 - 10
y = -2
ur numbers are 10 and -2
They would have played 20 games altogether
16 +28+32+4=80 80 total coins x.15 =12 coins sold
P(both work) = ((10-3)/10)*((10-3-1)/9) = (7/10)*(6/9) = 42/90
<span>P(at least one does not work) = 1 - P(both work) = 1 - 42/90 = 48/90 = 24/45.</span>
Answer:
2500
Step-by-step explanation:
it is a geometric progression
r=5
