De mediaan 8/10 - 7/10 - 7/10 - 3/10 - 4/10 - 0/10 - 10/10 - 5/10 - 3/10 - 1/10

Mathematics

2 answers:

Cerrena [4.2K]2 years ago

7 0

Answer:

The fifth and sixth number would be the median.Therefore its 4/10 or 0/10

dmitriy555 [2]2 years ago

7 0

Answer:

median is 4/10 or 0/10

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70 POINTS SHOW WORK

lord [1]

Area of triangle = 1/2 x base x height

so old triangle we have 1/2 x b x h = 48

new triangle has base 3 times as long and height is half as long
so we would get:

1/2 x (3B) x (1/2H) = area

rewrite as 1/2 x 3/2 x b x H = area

divide by original are os 1/2 x b x h and you end up with 3/2

so new area = 3/2 x old area

new area = 3/2 * 48 = 72 square inches

8 0

3 years ago

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andreyandreev [35.5K]

Using the Distributive Property

The answer would be 3.

2 *4x = 8x and 2 * 3 = 6, to get 8x 6

5 0

2 years ago

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zhannawk [14.2K]

Answer:

V = 137.2

Step-by-step explanation:

We are given the volume equation. Simply plug in your <em>r</em> into the equation and calculate and you should get 137.189 as your answer.

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2 years ago

What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$