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Vikentia [17]
3 years ago
7

De mediaan 8/10 - 7/10 - 7/10 - 3/10 - 4/10 - 0/10 - 10/10 - 5/10 - 3/10 - 1/10

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0

Answer:

The fifth and sixth number would be the median.Therefore its 4/10 or 0/10

dmitriy555 [2]3 years ago
7 0

Answer:

median is 4/10 or 0/10

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What is 2.8×4.6 find the missing partial products
cupoosta [38]
To find each box, you have to multiply the number above the box and the number to the left of the box.

For the bottom left, we have 4 x 0.8 or 3.2.

For the bottom right, we have 0.8 x 0.6 or 0.48.
7 0
3 years ago
Question 2(Multiple Choice Worth 1 points)
kramer

Answer:

it is a linear expression

6 0
2 years ago
Which of the following is the correct factored form for the given equation? 2x^2+8x+6=0
3241004551 [841]
It would be 2(x+3)(x+1)=0

Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
6 0
3 years ago
Nationwide, it is estimated that 40% of service stations have gas tanks that leak to some extent. A new program in California is
fredd [130]

Answer:

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

Step-by-step explanation:

The sample proportion is p2= 7/27= 0.259

and q2= 0.74

The sample size = n= 27

The population proportion = p1= 0.4

q1= 0.6

We formulate the null and alternate hypotheses that the new program is effective

H0: p2> p1   vs  Ha: p2 ≤ p1

The test statistic is

z= p2- p1/√ p1q1/n

z= 0.259-0.4/ √0.4*0.6/27

z=  -0.141/0.09428

z= -1.496

The significance level ∝ is 0.05

The critical region for one tailed test is z ≤ ± 1.645

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

8 0
3 years ago
Solve each pair of simultaneous equations by substitution method
WARRIOR [948]

Answer:

x = 1       y = -4

Step-by-step explanation:

- Plug the value of y into the other equation.

x + 3y = -11

x + 3(-4x) = -11

x - 12x = -11

-11x = -11

x = 1

- Now substitute the value of x into any equation.

y = -4x

y = -4(1)

y = -4

3 0
2 years ago
Read 2 more answers
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