Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is
Generally the sample proportion is mathematically represented as
=>
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
Answer:
Step-by-step explanation:
Given
Required
How far did they row together
To do this, we simply add the distance they both covered.
This gives;
Take LCM
Simplify
<em>Hence, they both rowed 1/2 mile</em>
Distributive property because if you divide -5.2+(-8.4) by -1, you get -(5.2+8.4)
Answer:
i think it is S
Step-by-step explanation:
i took the test on k12