Answer:
for m1=0.2
M2=0.4
for m1=2.5
M2=5
1= channel input
2.channel output
Explanation:
Hello!
To solve this problem follow the steps below!
1.As it is an isentropic system, it means that the temperature of the fluid remains constant, so the volumetric flow is the same, remember that this is calculated by calculating the product between the velocity and the area.
V1A1=V2A2
1= channel input
2.channel output
We can divide both sides of the equation by the speed of sound(V)
2. The mach number is defined as the ratio between the speed of a fluid and the speed of sound,
we rearrange the equation
M1A1=M2A2
3.Now considering that the channel is convergent and that the ratio between the areas is 2, we have the following equation (A1 / A2 = 2)
M1(2)=M2
4.Finally we solve for the number of mach indicated (0.2 and 2.5)
for m1=0.2
0.2(2)=M2=0.4
for m1=2.5
2.5(2)=M2=5
Answer:
One gallon of paint can cover about 400 square feet of wall.
18 x 15 feet is 270 feet of space.
270/400 = .675 gallons for one coat on one wall
.675 x 4 = 2.7 gallons for one coat on all walls
2.7 gallons x 2 = 5.4 gallons of paint in all
Answer: 0.2m sqr
Explanation:
A well behaved aircraft basically have a value of volume in horizontal and vertical area.
Volume in horizontal area (Vh) = 0.6
Volume in vertical area (Vv) = 0.05
Having known this, consider the relationship to find the vertical and horizontal tail sizes.
Vertical tail area (Sv)
Horizontal tail area (Sh)
Vh= (Sh × I) / S
Where,
I = moment
S= wing area
Sh= Horizontal tail area
Vh= Volume in horizontal area
0.6= Sh × 10/40
24= 10Sh
Sh= 24/10
Sh= 2.4 msqr
Horizontal tail area= 2.4m sqr
From the information above, we can calculate the vertical tail area.
Vertical tail area is calculated thus below:
Vv= (Sv× I) / S
Where
Vv= Volume in vertical area
Sv= Vertical tail area
I= Moment
S= Wing area
Therefore
Sv= (Vv × S) /I
Sv= (0.05×40)/10
Sv= 0.2msqr
In conclusion, the vertical tail size is 0.2msqr
Answer:
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Explanation:
