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3 years ago

Some cars have an FCW, which stands for

Engineering

1 answer:

Natalka [10]3 years ago

8 0

Answer:

FCW in car stands for Forward Collision Warning. 

Explanation:

The vehicle speed is monitored by FCW system, this is an advanced technology which indicates to the rear vehicle that a crash is going to happen if the vehicle gets close because of speed. This FCW systems monitor’s distance between the vehicles and speed of the vehicles.

FCW system do not control the vehicle completely. This system consists of sensors to detect stationary or slower-moving vehicles. A signal alerts the driver if the distance between the vehicles is less so that crash is being happened. It helps driver from crash by changing his route. Cars with this technology consists of audible alert.

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Which one of the following is not an economic want?

Nostrana [21]

The available options are:

a. Want for a television set

b. Want for medical attention

c. Want for friendship

d. Want for new clothing

Answer:

Want for friendship

Explanation:

Given that economic want is what humans desire to have or possess such that they pay money to acquire them.

Hence, from the available options "want for friendship " is not economic want because it can't be bought with money, while other options can be bought with money or monetary transaction.

8 0

3 years ago

. H Kijwhayhwbbwyhwbwbwgwwgbwbwhwh

dsp73

Yes. Gggggggggghhhhh

3 0

3 years ago

Read 2 more answers

A vacuum pump is used to drain a basement of 20 °C water (with a density of 998 kg/m3 ). The vapor pressure of water at this tem

lord [1]

Answer:

The maximum theoretical height that the pump can be placed above liquid level is $\Delta h=9.975\,m$

Explanation:

To pump the water, we need to avoid cavitation. Cavitation is a phenomenon in which liquid experiences a phase transition into the vapour phase because pressure drops below the liquid's vapour pressure at that temperature. As a liquid is pumped upwards, it's pressure drops. to see why, let's look at Bernoulli's equation:

$\frac{\Delta P}{\rho}+g\, \Delta h +\frac{1}{2} \Delta v^2 =0$

( $\rho$ stands here for density, $h$ for height)

Now, we are assuming that there aren't friction losses here. If we assume further that the fluid is pumped out at a very small rate, the velocity term would be negligible, and we get:

$\frac{\Delta P}{\rho}+g\, \Delta h =0$

$\Delta P= -g\, \rho\, \Delta h$

This means that pressure drop is proportional to the suction lift's height.

We want the pressure drop to be small enough for the fluid's pressure to be always above vapour pressure, in the extreme the fluid's pressure will be almost equal to vapour pressure.

That means:

$\Delta P = 2.34\,kPa- 100 \,kPa = -97.66 \, kPa\\$

We insert that into our last equation and get:

$\frac{ \Delta P}{ -g\, \rho\,}= \Delta h\\\Delta h=\frac{97.66 \, kPa}{998 kg/m^3 \, \, 9.81 m/s^2} \\\Delta h=9.975\,m$

And that is the absolute highest height that the pump could bear. This, assuming that there isn't friction on the suction pipe's walls, in reality the height might be much less, depending on the system's pipes and pump.

8 0

3 years ago

(Signal Property) Under what condition is a discrete-time signal x[????] or a continuous-time signal x(????) periodic? Determine

Cloud [144]

Answer:

a. 2x/3

b. 8

Explanation:

fundamental period can be defined to mean that at after every period of 2π radians or 360° the value of graph is repeated. For such functions the fundamental period is the period after which they repeat themselves.

It van also be looked as The fundamental period of cos(θ) is 2π. That is (for example) cos(0) to cos(2π) represents one full period.

Please see attachment for the step by step solution.