Answer:
2062 lbm/h
Explanation:
The air will lose heat and the oil will gain heat.
These heats will be equal in magnitude.
qo = -qa
They will be of different signs because one is entering iits system and the other is exiting.
The heat exchanged by oil is:
qo = Gp * Cpo * (tof - toi)
The heat exchanged by air is:
qa = Ga * Cpa * (taf - tai)
The specific heat capacity of air at constant pressure is:
Cpa = 0.24 BTU/(lbm*F)
Therefore:
Gp * Cpo * (tof - toi) = Ga * Cpa * (taf - tai)
Ga = (Gp * Cpo * (tof - toi)) / (Cpa * (taf - tai))
Ga = (2200 * 0.45 * (150 - 100)) / (0.24 * (300 - 200)) = 2062 lbm/h
Answer:
Parallel
Explanation:
The devices are connected in parallel.
This is because the wiring of the standard home is done in such a manner that all the outlets are in parallel.
The outlets are kept in parallel connection so that appliance connected to each outlet should receive equal amount of voltage i.e the voltage received at the house.
Answer: The number of gram of ammonia gas (
) contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Explanation:
Given: Volume = 3.0 L
Temperature = 305 K
Pressure = 1.50 atm
Formula used to calculate the number of moles is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
![PV = nRT\\1.50 atm \times 3.0 L = n \times 0.0821 L atm/mol K \times 305 K\\n = \frac{1.50 atm \times 3.0 L}{0.0821 L atm/mol K \times 305 K}\\= \frac{4.5}{25.0405}\\= 0.179 mol](https://tex.z-dn.net/?f=PV%20%3D%20nRT%5C%5C1.50%20atm%20%5Ctimes%203.0%20L%20%3D%20n%20%5Ctimes%200.0821%20L%20atm%2Fmol%20K%20%5Ctimes%20305%20K%5C%5Cn%20%3D%20%5Cfrac%7B1.50%20atm%20%5Ctimes%203.0%20L%7D%7B0.0821%20L%20atm%2Fmol%20K%20%5Ctimes%20305%20K%7D%5C%5C%3D%20%5Cfrac%7B4.5%7D%7B25.0405%7D%5C%5C%3D%200.179%20mol)
It is known that moles is the mass of substance divided by its molar mass.
Hence, mass of ammonia gas (molar mass = 17.03 g/mol) is as follows.
![Moles = \frac{mass}{molar mass}\\0.179 mol = \frac{mass}{17.03 g/mol}\\mass = 3.048 g](https://tex.z-dn.net/?f=Moles%20%3D%20%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D%5C%5C0.179%20mol%20%3D%20%5Cfrac%7Bmass%7D%7B17.03%20g%2Fmol%7D%5C%5Cmass%20%3D%203.048%20g)
Thus, we can conclude that the number of gram of ammonia gas (
) contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
The magnitude of shear stress (kPa) on an element a lying at a distance of 20 mm from neutral axis. (6 pts) are given, p = 2kn e = 210gpa distance from constant cease = 20mm = 0.2m.
<h3>What is the cantilever formula?</h3>
The cantilever beam equations (deflection) w = load. l = member length. e = young's modulus. i = the beam's moment of inertia.
- theta= 2000 2*210*10^ 9 * (0.006)^ four 12 [(0.1)^ 2 -(0.08)^ 2 ] =0.1587 rad
- ø at q i.e. x = 100 - 20 = 80mm = 0.08m from loose cease.
- theta = p/(2ei) * (l ^ 2 - x ^ 2) phase of facet a. i = (a ^ four)/12 for square.
Read more about the cantilever beam :
brainly.com/question/16791806
#SPJ1
1.25, because change the fractions into decimals and then add it from there so it would be add like, 0.75+0.5=1.25