Answer:
∠ABC = 100°
∠ADF = 100°
Step-by-step explanation:
(8x + 4)° = (10x - 20)°
(2x)° = 24°
x = 12°
Compute, knowing that x = 12°
8x + 4 = 8 · 12 + 4 = 100°
10x - 20 = 10 · 12 - 20 = 100°
Answer:
A. 30 meters
Step-by-step explanation:
Let's find the answer.
The problem established a quadratic relationship between height (h) and time (t), then we can establish:
h(t)=K*t where 'K' is a coefficient.
Because an experiment was done, we can find 'K' as follows:
h(t)=K*t
90meters=K*(3seconds)
90meters/3seconds=K
30m/s=K
Now we can solve the problem, so for 2 seconds:
h(t)=K*t
h(t)=(30m/s)*(2s)
h(t)=60m
But notice that the obtained 60 meters are the distance traveled in 2 seconds from the top the building to the ground. So 'how far from the ground' can be calculated as:
(far from the ground) = (total building height) - (distance traveled in 2s)
(far from the ground) = 90m - 60m = 30m
In conclusion, after 2 seconds, the ball is 30 meters far from the ground. The answer in then A. 30 meters.
Answer:
Step-by-step explanation:
1 yes 2 no 3 no 4 yes 5 no
Answer:
Let the matrix associated to the system and
the vector of constant values of the system.
The equation of the line joining p and q is
. Since p and q are solutions of the linear system then, and
Let . Observe that . Then w is a solution of the homogeneous system Ax=0.
Now, let s=p+r(q-p) for some be a point in the line joining p and q. Observe that
Then As=b. This means that s is a solution of the linear system.
Answer:
The answer is D
Step-by-step explanation:
If you plug them into Desmos, they'll line up