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DedPeter [7]
3 years ago
13

Plz help I’m bad at algebraic expressions and translating them.

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

1. 4+n

2. n-9

3. 2n + 6

4. n/6

5. 2(n+3)

Step-by-step explanation:

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Help me with this math assesment please<br><br> 15 points!!!!!!!
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Answer:

for part a i think it is the second one sorry if i do get it wrong and i couldnt answer the last one sorry

Step-by-step explanation:

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2 years ago
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In the given diagram, which of the following pairs of angles are alternate interior angles?
castortr0y [4]

Answer:

3 and 6

4 and 5

Step-by-step explanation:

Alternate interior angles are on the opposite sides of the transversal, t, and between the parallel lines, r and s

3 and 6 are alternate interior angles

4 and 5 are alternate interior angles

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2 years ago
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Two-fifths of the students in 6th grade are in the band, Of these, one-
Gelneren [198K]

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1/10 or 10%

Step-by-step explanation:

1/4 x 2/5 = 1/10 (10%)

3 0
3 years ago
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
3 years ago
Se vendieron un total de 430 boletos para la obra de teatro escolar. Los boletos eran o de adulto o de estudiante. Se vendieron
BartSMP [9]

Resolviendo un sistema de ecuaciones, veremos que se vendieron 250 boletos de adulto.

<h3>¿Cuántos boletos de adulto fueron vendidos?</h3>

Definamos las variables:

  • x = boletos de adulto vendidos.
  • y = boletos de estudiantes vendidos.

Se vendieron un total de 430 boletos, entonces:

x + y = 430

Y se vendieron 70 boletos de estudiante menos que boletos de adulto:

y = x - 70

Tenemos el sistema de ecuaciones:

x + y = 430

y = x - 70

Para resolverlo, podemos reemplazar la segunda ecuación en la primera:

x + y = 430

x + (x - 70) = 430

2x = 430 + 70 = 500

x = 500/2 = 250

Se vendieron 250 boletos de adulto.

Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

#SPJ1

5 0
2 years ago
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