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Korolek [52]
3 years ago
14

5x-25=50 3x+9=90 n solve both equations

Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

1st is x=15

2nd is x=27

Step-by-step explanation:

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The smallest positive solution of tan bx = 2 is x = 0.3. Determine the general solution of tan bx = 2.
Contact [7]

The general solution of tan(b·x) = 2, given that the smallest positive solution is x = 0.3, is presented as follows;

\mathbf{ x =0.3 +  \dfrac{n \cdot \pi}{b}}

The given smallest positive solution of tan (b·x) = 2 is x = 0.3

The general solution of tan (b·x + c) = m, is given as follows;

\mathbf{x = \dfrac{\alpha  - c}{b}  + n \cdot \dfrac{\pi}{b}}

α = arctan(m) = x₀

The minimum positive value of the general solution is therefore presented as follows;

x_{min \ positive} = \dfrac{\alpha  - c}{b}  + 0 \times \dfrac{\pi}{b} = \dfrac{\alpha  - c}{b}

\mathbf{x_{min \ positive} = \dfrac{\alpha  - c}{b}}

In the given function, tan (b·x), we therefore, have;

c = 0, m = 2,  \dfrac{\alpha  - c}{b} = 0.3

The general solution of tan(b·x) = 2, is therefore;

\mathbf{x =0.3 +  \dfrac{n \cdot \pi}{b}}

Learn more about the general solution of a sine function here:

https://brainly.in/question/1549935

5 0
3 years ago
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Given: AB≅ BC and AK ≅ KC, ∠AKE ≅ ∠CKP, Prove: ∆AKE ≅ ∆CKP<br> PLEASE HELP!!!!!!!!!!!!!
timofeeve [1]

Answer:

Step-by-step explanation:

Given:

AB ≅ BC

AK ≅ KC

∠AKE ≅ ∠CKP

To Prove:

ΔAKE ≅ ΔCKP

         Statements                               Reasons

1). AB ≅ BC                                          1). Given

2). ∠BAC ≅ ∠BCA                              2). Property of Isosceles triangles

3). ∠EKA ≅ ∠PKC                               3). Given

4). ΔAKE ≅ ΔCKP                               4). ASA Postulate of congruence

Hence ΔAKE ≅ ΔCKP.

3 0
3 years ago
PLEASE HELP!!!! HELP HELP!
monitta

Answer: D: Half turn about the origin

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3 years ago
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What’s is the answer please?
Vesna [10]
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(1/10)/10
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4 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use for the fraction bar(s).
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a= 7 , b=9 , c=4 because if you take an example like

\sqrt{x}  = {x}^{ \frac{1}{2} }

so the a=x b=1 c=2

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