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Korolek [52]
3 years ago
14

5x-25=50 3x+9=90 n solve both equations

Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

1st is x=15

2nd is x=27

Step-by-step explanation:

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To increase or decrease an amount by 30% what single multiplier would you use?
Nataly_w [17]
100%-30%=70%
100%+30%=130%

to decrese by 30%, multiply by 70%
to increase by 30%, multiply by 130%

5 0
3 years ago
Read 2 more answers
The sum of two numbers is 95. If the larger is increased by twice the smaller, the result is 120. Find the numbers.
adelina 88 [10]
Hello!

You can make two expressions based on what you know

let x equal the larger number
let y equal the smaller number

x + y = 95
x + 2y = 120

We can use elimination to get rid of x

You can subtract the two equation to get rid of x

-y = -25

Since y is negative we can multiply both sides by -1 to make y positive

y = 25

Now we can put this into one of the other equations to find x

x + 25 = 95

subtract 95 from both sides

x = 70

The answers are 70 and 25

Hope this helps!
3 0
3 years ago
-1/2, -2, -8, -32<br> Is this geometric, arithmetic, or neither?
serg [7]

Answer:

Neither

Step-by-step explanation:

4 0
3 years ago
Earth revolves around the Sun in 365 days, but the planet Mercury does so in only 88 days. Compared to Earth, how many more comp
Elena L [17]

Answer:

In a 1000 days Mercury will make 8.624 more revolutions than Earth!

Step-by-step explanation:

<u>Earth</u> takes 365 days to make a complete revolution.

we can say that the rotational speed of Earth is \dfrac{1}{365}\frac{\text{rev}}{\text{day}}

so, in a 1000 days how many revolutions will Earth have made?

\dfrac{1}{365}\frac{\text{rev}}{\text{day}}\times(1000\,\text{day})

see that the 'day's cancel out. Simply multiply the two numbers!

2.739\text{rev}

<u>Next, do the same for Mercury</u>

we can say that the rotational speed of Mercury is \dfrac{1}{88}\frac{\text{rev}}{\text{day}}

as it completes 1 revolution in 88 days.

so, in a 1000 days how many revolutions will Mercury have made?

\dfrac{1}{88}\frac{\text{rev}}{\text{day}}\times(1000\,\text{day})

multiplying by 1/88 by 1000 yields:  

11.363\text{rev}

The Question is how many MORE complete revolutions will Mercury make in 1000 days?

We need to subtract the revolutions of Mercury with Earth to find how far ahead is Mercury from Earth

11.363\text{rev} - 2.739\text{rev}

8.624\text{rev}

In a 1000 days Mercury will make 8.624 more revolutions than Earth!

5 0
3 years ago
F(a)=|x-6|-|x+5|<br><br> evaluate
Aleksandr-060686 [28]
X=1/2
Alternative: 0.5 or 2^-1
3 0
3 years ago
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