The general solution of tan(b·x) = 2, given that the smallest positive solution is x = 0.3, is presented as follows;

The given smallest positive solution of tan (b·x) = 2 is x = 0.3
The general solution of tan (b·x + c) = m, is given as follows;

α = arctan(m) = x₀
The minimum positive value of the general solution is therefore presented as follows;


In the given function, tan (b·x), we therefore, have;
c = 0, m = 2, 
The general solution of tan(b·x) = 2, is therefore;

Learn more about the general solution of a sine function here:
https://brainly.in/question/1549935
Answer:
Step-by-step explanation:
Given:
AB ≅ BC
AK ≅ KC
∠AKE ≅ ∠CKP
To Prove:
ΔAKE ≅ ΔCKP
Statements Reasons
1). AB ≅ BC 1). Given
2). ∠BAC ≅ ∠BCA 2). Property of Isosceles triangles
3). ∠EKA ≅ ∠PKC 3). Given
4). ΔAKE ≅ ΔCKP 4). ASA Postulate of congruence
Hence ΔAKE ≅ ΔCKP.
Answer: D: Half turn about the origin
With 10 spots between each 1/10th, the equation for each space would be
(1/10)/10
(Simplify)
1/10*10
1/100
FRACTION: 13/100
DECIMAL: 0.013
a= 7 , b=9 , c=4 because if you take an example like

so the a=x b=1 c=2