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Nana76 [90]
3 years ago
15

Find the perimeter of the polygon with the vertices G(2, 4), H(2,−3), J(−2,−3), and K(−2, 4).

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

<em>22 units</em>

Step-by-step explanation:

Graphed to solve.

Width:

The distance between points K and G, and points J and H is both 4 units. So for both distances between the set of points will be 8 units total.

Length:

The distance between points G and H, and points J and K is both 7 units. So for both distances between the sets of points will be 14 units total.

14 + 8 = 22

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3 similar shirts and 4 similar jackets cost $360. 1 such shirt and 3 such jackets cost $220. Find the costof each shirt.
Lyrx [107]
3s + 4j = 360
1s + 3j = 220

This one we can solve using substitution, in that
s + 3j = 220 implies s = 220 - 3j (subtract 3j from each side).

Now substitute into the first equation:

3(220 - 3j) + 4j = 360.  Solve for jackets.
660 - 9j + 4j = 360  [Distributive property]
660 - 5j = 360 [Add -9j + 4j]
Subtract 360 from each side, and add 5j to each side.
660 - 360 - 5j + 5j = 360 - 360 + 5j
300 = 5j
Divide each side by 5.
$60 = price of a jacket.

Three of these plus a shirt runs $220.
3(60) = 180
180 + s = 220
180 - 180 + s = 220 - 180 [Subtract 180 from each side]
s =   40

Now we double check.
3(40) + 4 (60) = 120 + 240 = 360.  This satisfies the first equation.
We could check the second one too, but I'm satisfied.
4 0
3 years ago
The scatter plot below shows the height of a tree over time. What is the approximate height of the tree after 10 years show work
gladu [14]
17ft, you go across x-axis till 10(years) and vertically look up to the line which co-ordinates x-axis with y-axis and look up the height(ft)
3 0
3 years ago
PLEASE HELP! image below
Viktor [21]

Answer:  Angle BAD

We don't see the list; it's also called angle DAB.

4 0
3 years ago
Read 2 more answers
Help me asap! <br><br><br> please help
OLEGan [10]

cross multiply:

21*9 = 189

7*q = 7q

so you have 189/7q

 divide 189 by 7 to get q

189 / 7 =27

q = 27

8 0
3 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0
3 years ago
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