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3 years ago

Which of the following is a transition element A)H B) He C) Fr D) Rn E) Rh

Chemistry

1 answer:

muminat3 years ago

4 0

Answer:

rh, e

Explanation:

rhodium is a transition element

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- Write equations for (a) the decomposition of carbon monoxide-

allsm [11]

Explanation:

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3 years ago

If a reaction occurs, what will be the products of the unbalanced reaction below?

castortr0y [4]

Explanation:

I think the correct answer is B

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8 0

3 years ago

Which of the following represents the least number of molecues?

Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

$molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}$

So, let´s get the number of molecules for each of the options.

$a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules$

$b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules$

$c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules$

$d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules$

$d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules$

the smalest number is in option a)

Best of luck.

7 0

3 years ago

If you mix water with your urine drug test will you pass

masya89 [10]

<span>A "dilute specimen" is a urine sample that has a higher than average water ... even if the drug is detected, it will not be marked as a positive result because ... Powdered urine can be purchased online in packets, and then mixed with water to form urine. ... so they would report your test as negative andyou'd get hired anyway.</span><span>
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3 years ago

Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve

Alex73 [517]

The answer is 1.5*10^-12 square meters. For a detailed calculation, please refer to the attachment.

Download docx

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3 years ago