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Nimfa-mama [501]
3 years ago
13

Which of the following is a transition element A)H B) He C) Fr D) Rn E) Rh

Chemistry
1 answer:
muminat3 years ago
4 0

Answer:

rh, e

Explanation:

rhodium is a transition element

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What is the percent error for the experiment if the actual density is
OLga [1]

Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 2.49g/mL

error = 2.49 - 1.47 = 1.02

We have

p(\%) =  \frac{1.02}{2.49}  \times 100 \\ = 40.96385542...

We have the final answer as

<h3>40.96 %</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
What should go in the blank?
dem82 [27]

Answer:

³⁸₂₀Ca.

Explanation:

³⁸₁₉K –> __ + ⁰₋₁β

Let ʸₓA represent the unknown.

Thus the equation above can be written as:

³⁸₁₉K –> ʸₓA + ⁰₋₁β

Thus, we can obtain the value of y an x as follow:

38 = y + 0

y = 38

19 = x + (–1)

19 = x – 1

Collect like terms

19 + 1 = x

x = 20

Thus,

ʸₓA => ³⁸₂₀A => ³⁸₂₀Ca

Therefore, the equation is:

³⁸₁₉K –> ³⁸₂₀Ca + ⁰₋₁β

6 0
3 years ago
Which of the following chemical equations is balanced?
muminat

Answer:

A, 4Fe 3O2 → 2Fe2O3

5 0
3 years ago
A 26.08 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reac
Over [174]

Answer:

Molar percent of sodium in original mixture is 88,50%

Explanation:

The last reaction is:

BaCl₂ + Na₂SO₄ → BaSO₄ + 2 NaCl

The moles of BaCl₂ are:

0,132L × 3,80M = 0,502 moles of BaCl₂

As the amount of BaCl₂ is the maximum possible to produce BaSO₄, the moles of BaCl₂ must be the same than moles of Na₂SO₄.

0,502 moles of BaCl₂ ≡ 0,502 moles of Na₂SO₄

These moles of Na₂SO₄ comes from:

2 Na + H₂SO₄ → Na₂SO₄ + H₂

As the reaction is in stoichiometric amounts, moles of Na are twice the moles of Na₂SO₄

0,502 moles of Na₂SO₄ ×\frac{2molesNa}{1moleNa_{2}SO_{4}}× 22,99 g/mole = 23,08 g of Na

Molar percent of sodium in original mixture is:

\frac{23,08g}{26,08g}*100 = <em>88,50% </em>

I hope it helps

4 0
3 years ago
The specific heat capacity of concrete is 0.880 J/g °C
LenaWriter [7]

Answer:

this is a required answer. look it once.

3 0
3 years ago
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