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Ray Of Light [21]
3 years ago
13

Calculate the mass and charge of one mole of electrons​

Chemistry
1 answer:
arsen [322]3 years ago
4 0

Answer:

I don't know if this is really helpful or not, but an electron weights 0.00000000000000000000000000091 grams.

Explanation:

May I have brainliest please? :)

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For chemical reactions involving ideal gases, the equilibrium constant K can be expressed either in terms of the concentrations
miskamm [114]

Answer:

K_p= 3966.01

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2CH_4_{(g)}\rightleftharpoons C_2H_2_{(g)}+3H_2_{(g)}

Given: Kc = 0.140

Temperature = 1778 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (1778 + 273.15) K = 2051.15 K  

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (3+1)-(2) = 2  

Thus, Kp is:

K_p= 0.140\times (0.082057\times 2051.15)^{2}

K_p= 3966.01

6 0
3 years ago
The unit used to measure barometric or air pressure
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Answer:

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Explanation:

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7 0
4 years ago
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