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Ray Of Light [21]
2 years ago
13

Calculate the mass and charge of one mole of electrons​

Chemistry
1 answer:
arsen [322]2 years ago
4 0

Answer:

I don't know if this is really helpful or not, but an electron weights 0.00000000000000000000000000091 grams.

Explanation:

May I have brainliest please? :)

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3. When two atoms bond together to form a molecule, which parts of the atoms
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Which metals have similar chemical properties? Check all that apply. barium beryllium rubidium radium titanium calcium platinum
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Read 2 more answers
Fill in the blanks for the following statements: The rms speed of the molecules in a sample of H2 gas at 300 K will be _________
Anna007 [38]

Answer : The rms speed of the molecules in a sample of H_2 gas at 300 K will be four times larger than the rms speed of O_2 molecules at the same temperature, and the ratio \mu _{rms}(H_2)/\mu _{rms}(O_2) constant with increasing temperature.

Explanation :

Formula used for root mean square speed :

\mu _{rms}=\sqrt{\frac{3RT}{M}}

where,

\mu _{rms} = rms speed of the molecule

R = gas constant

T = temperature

M = molar mass of the gas

At constant temperature, the formula becomes,

\mu _{rms}=\sqrt{\frac{1}{M}}

And the formula for two gases will be,

\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{M_{O_2}}{M_{H_2}}}

Molar mass of O_2 = 32 g/mole

Molar mass of H_2 = 2 g/mole

Now put all the given values in the above formula, we get

\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{32g/mole}{M_{2g/mole}}}=4

Therefore, the rms speed of the molecules in a sample of H_2 gas at 300 K will be four times larger than the rms speed of O_2 molecules at the same temperature.

And the ratio \mu _{rms}(H_2)/\mu _{rms}(O_2) constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.

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3 years ago
Write a balanced chemical equation for the neutralization reaction between phosphoric acid and lithium hydroxide.
Akimi4 [234]
Hope that helps!!!!!!!

5 0
3 years ago
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