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lubasha [3.4K]
4 years ago
10

1.

Chemistry
1 answer:
natta225 [31]4 years ago
4 0
The Moon completes one orbit around the Earth in approximately 27 1/3 days and completes one cycle of its phases in approximately 29 1/2 days. The correct option among all the options that are given in the question is the second option. I hope that this is the answer that has come to your great help.
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Which of the following has the greatest mass? 1 mole of uranium (U) 1 mole of oxygen (O) 1 mole of sodium (Na) 1 mole of chlorin
Lelu [443]
To determine which has the greatest mass, we need to find out the molecular mass of each element:

Uranium (U) = 238 g/mol
Oxygen (O) = 16 g/mol
Sodium (Na) = 23 g/mol
Chlorine (Cl) = 35.45 g/mol

Therefore, if we have one mole of each element, the element with the greatest mass is 238 grams or <u>Uranium.</u><span />
3 0
4 years ago
Read 2 more answers
What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?
BaLLatris [955]
<h2>Hello!</h2>

The answer is:

The third option, 79.8%

<h2>Why?</h2>

To calculate the percent yield we need to divide the actual yield by the theoretical yield, and then, multiply it by 100 in order to find the percent.

So, we from the statement we know the following information:

ActualYield=220.0g\\TheoreticalYield=275.6g

Let's use the following formula and substitute the given information:

PercentYield=\frac{ActualYield}{Theoretical}*100\\\\

PercentYield=\frac{220g}{275.6g}*100=0.798*100=79.8(percent)

Hence, we have that the correct option is the third option, the percent yield is 79.8%.

Have a nice day!

7 0
3 years ago
Molecule Energy Released
charle [14.2K]
Carbohydrate; contains a low ratio of oxygen atoms.
4 0
3 years ago
Read 2 more answers
Describe, in detail, to a freshman undergraduate how to make 1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /m
mario62 [17]

Answer:

Explanation:

The objective here is to prepare  1 liter of LB + Kan (100 μg/ml final concentration) + Amp (50 μg /ml final concentration) liquid media.

Given that :

the Stock concentration of Amp: 100 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in  μg/ml since 100 mg/ml = 100000  μg/ml

However, using formula C₁V₁=C₂V₂ (Ampicilin),

where:

C₁ = 100000 μg/ml,

V₁=?,

C₂= 50  μg/ml,

V₂=1000 ml

100000 μg/ml × V₁ = 50  μg/ml × 1000 ml

V₁ =  50  μg/ml × 1000 ml/100000 μg/ml

V₁ =   0.5 ml

Given that:

the Stock concentration of Kan: 25 mg/ml (since 1 mg/ml = 1000 μg/ml)

it is required that we convert stock concentration in  μg/ml , 25 mg/ml = 25000 μg/ml

Now by using formula C₁V₁=C₂V₂ (Kanamycin),

C₁ = 25000 μg/ml,

V₁=?,

C₂= 100  μg/ml,

V₂=1000 ml

25000 μg/ml × V₁ = 100  μg/ml × 1000 ml

V₁ =  100  μg/ml × 1000 ml/25000 μg/ml

V₁ =   4 ml

Thus; in 1 lite of Lb+ Kan+Amp preparation;

0.5 ml of Amp & 4 ml of kanamycin is used for their stock preparation.

Finally;

Sterilization step should be carried out in flask (Clean dry glass wares) for media in an autoclave, the container size should be twice the volume of media which is prepared.

5 0
4 years ago
How many moles of hydrogen molecules (h2) would be required to produce two moles of hydrogen peroxide (h2o2)?
SashulF [63]
Their should be two molecules of hydrogen (h2) to produce 2 moles of h2O2
3 0
4 years ago
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