Answer:
4/10
Step-by-step explanation:
10-6=4 therefore it is 4/10
Answer:
I put III
Step-by-step explanation:
89 vegetarian dishes
The unitary technique, in its most basic form, is used to calculate the value of a single unit from a specified multiple. How to determine the value of one pen, for instance, if the cost of 40 pens is Rs. 400. The unitary approach can be used to complete it. Additionally, after determining the value of a single unit, we can multiply that value by the number of units needed to determine the value of the additional units. The concept of ratio and proportion is mostly applied using this way.
Using unitary method,
152 passengers are served with = 27 dishes
1 passengers are served with = 27/152
500 passengers are served with = 27 x 500 / 152
= 88. 81
≈ 89 vegetarian dishes
To learn more about unitary method, refer to brainly.com/question/24587372
#SPJ9
Answer:
P = 2(L + W)
Step-by-step explanation:
P = 2L + 2W
Factor out a 2 from the right hand side
P = 2*L + 2 * W
P = 2(L + W)
Answer:
Both statements (1) and (2) TOGETHER are sufficient to answer the question asked; but NEITHER statement ALONE is sufficient.
Step-by-step explanation:
Solving the equation of statement (1) with the quadratic formula:
![x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![x^2+40x+391=0\\x_{1,2}=\frac{-40\pm\sqrt{40^2-4(1)(391)}}{2(1)}\\x_{1,2}=\frac{-40\pm\sqrt{1600-1564}}{2}\\x_{1,2}=\frac{-40\pm\sqrt{36}}{2}\\x_{1}=\frac{-40+6}{2}=\frac{-34}{2}=-17\\x_{1}=\frac{-40-6}{2}=\frac{-46}{2}=-23\\](https://tex.z-dn.net/?f=x%5E2%2B40x%2B391%3D0%5C%5Cx_%7B1%2C2%7D%3D%5Cfrac%7B-40%5Cpm%5Csqrt%7B40%5E2-4%281%29%28391%29%7D%7D%7B2%281%29%7D%5C%5Cx_%7B1%2C2%7D%3D%5Cfrac%7B-40%5Cpm%5Csqrt%7B1600-1564%7D%7D%7B2%7D%5C%5Cx_%7B1%2C2%7D%3D%5Cfrac%7B-40%5Cpm%5Csqrt%7B36%7D%7D%7B2%7D%5C%5Cx_%7B1%7D%3D%5Cfrac%7B-40%2B6%7D%7B2%7D%3D%5Cfrac%7B-34%7D%7B2%7D%3D-17%5C%5Cx_%7B1%7D%3D%5Cfrac%7B-40-6%7D%7B2%7D%3D%5Cfrac%7B-46%7D%7B2%7D%3D-23%5C%5C)
In this equation, one of the values of x is bigger than -20 but the other is smaller, this statement doesn't give enough information to answer the question.
Solving the quadratic equation of the statement (2):
![x^2=529\\x_{1,2}=\pm\sqrt{529} \\x_1=\sqrt{529}=23\\x_2=-\sqrt{529}=-23](https://tex.z-dn.net/?f=x%5E2%3D529%5C%5Cx_%7B1%2C2%7D%3D%5Cpm%5Csqrt%7B529%7D%20%5C%5Cx_1%3D%5Csqrt%7B529%7D%3D23%5C%5Cx_2%3D-%5Csqrt%7B529%7D%3D-23)
Again, one of the values of x is bigger than -20 and the other is smaller than -20. But if the information of this statement is considered along with the other x must be equal to -23, that is the value that appears as an answer in both equations, and with this information is possible to answer the question.