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3 years ago

6(3a-2b+c) expand this equation

Mathematics

2 answers:

Zepler [3.9K]3 years ago

4 0

Answer:

18a-12b+6c

Step-by-step explanation:

You times 6 by everything in the bracket,

6x3a= 18a

6x-2b= - 12b

6xc=6c

Then put them together for the answer,

18a+-12b+6c

Change any symbols that need changing,

18a-12b+6c

Hope this helps!

KonstantinChe [14]3 years ago

3 0

Answer:

18a-12b+6c

Step-by-step explanation:

We have got 6 common in this factor 6(3a-2b+c)

So,in order to expand it we just need to multiply 6 with the everything in the bracket..

6×3a=18a

6×2b=12b

6×c=6c

If we arrange the factor after multiplying,then it stands like this 18a-12b+6c...

(Ans)

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3 years ago

Determine the graph of the polar equation r =6/2-2cos theta.

anzhelika [568]

Answer:

Choice D is correct

Step-by-step explanation:

The first step is to write the polar equation of the conic section in standard form by dividing both the numerator and the denominator by 2;

$r=\frac{3}{1-cos(theta)}$

The eccentricity of this conic section is thus 1, the coefficient of cos θ. Thus, this conic section is a parabola since its eccentricity is 1.

The value of the directrix is determined as;

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Thus, the polar equation represents a parabola that opens towards the right with a directrix located at x = -3. Choice D fits this criteria

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3 years ago

Which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)

vagabundo [1.1K]

we have

$8x^2+13x - 6$

Equate the function to zero

$8x^2+13x - 6=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$8x^2+13x = 6$

Factor the leading coefficient

$8(x^2+\frac{13}{8}x) = 6$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$8(x^2+\frac{13}{8}x) = 6$

$8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16} \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2$