3x + 4y = 38 ( equation 1) ----> ×5
5x - 5y = -30 ( equation 2) ----> ×3
When you multiply eqn 1 by 5 you get, 15x + 20y = 190
And when you multiply eqn 2 by 3, you get, 15x - 15y = -90
Then you solve both equations by subtracting eqn 2 from eqn 1
15x + 20y = 190
15x - 15y = 90
Then 15x - 15x gets cancelled and 20y - (-15y) gives 35y and 190 - (-90) gives 280.
So that gives 35y = 280
y = 8
And when you replace y = 8 in any of the two equations, x = 2
Height = x (This is given)
Length = 5x
Width = 6x
Volume = length × width × height
The equation will be: (5x)(6x)(x) = 1920
simplify:
30x² × (x) = 1920
30x³ = 1920
Divide both sides by 30
x³= 64
x = ∛64
x= 4
If x = height, then, the height is 4cm
5x = length
20cm = length
6x = width
24cm = width
Answer:
Length =
= 5/2 inches or 2 1/2 inches
Step-by-step explanation:
Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil 11 1 4 is square inches. Its length is 4 1 2 inches. What is the width of the foil? Explain your reasoning.
Area of rectangle = Length × Width
Widths = Area/Length
The area of the rectangular piece of foil 11 1/4 is square inches.
Its length is 4 1 /2 inches.
Hence:
Length = 11 1/4 /4 1/2
= 45/4 ÷ 9/2
= 45/4 × 2/9
= 5/2 inches
= 2 1/2 inches
Answer:
Since the footrest measures 1.54 square yards, Alice will not be able to cover it completely.
Step-by-step explanation:
Since Alicia wants to cover a footrest in the shape of a rectangular prism with cotton fabric, and the footrest is 14 inches by 11 inches by 13 inches while she has 1 square yard of fabric, to determine if she can she completly cover the footrest the following calculation must be performed:
1 square yard = 1296 square inches
14 x 11 x 13 = X
154 x 13 = X
2.002 = X
2.002 / 1.296 = 1.54
Thus, since the footrest measures 1.54 square yards, Alice will not be able to cover it completely.
Answer:
<h2>C) PA = PB</h2>
Step-by-step explanation:
AB = PB + PA
PC is the perpendicular bisects of the segment BA.
Therefore PB = PA → AB = 2PB = 2PA → PB = PA = 1/2AB.
