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BabaBlast [244]
2 years ago
6

What is a domain in the following expression? 1/x I will mark brainliest

Mathematics
1 answer:
xeze [42]2 years ago
6 0

Answer:

The set of all first components of the ordered pairs of relation R is called domain

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A 271⁄2-mile stretch of road needs repaving. A company bid on the repaving project, saying they could repave 21⁄4 miles of road
harkovskaia [24]

Answer:

D.)12 2/9

Step-by-step explanation:

27 1/2 / 2 1/4= 12 2/9

7 0
3 years ago
Read 2 more answers
Eric wants to get an output of 0. Can he do this with each machine? If so, how? If not, why not?
natita [175]

Answer:

  • <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>

Explanation

The way each machine works is given by the expression (function) inside it.

<u>1)  </u><em><u>Function A</u></em>

To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.

Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.

<u>2) </u><em><u>Function B</u></em>

Solve y=\sqrt{x}-2=0

  • \sqrt{x}-2=0

  • \sqrt{x} =2

  • x=2^{2}

  • x=4

So, he can get an output of 0 by using x = 4.

4 0
3 years ago
Giving brainliest to CORRECT answer.
klasskru [66]

Answer:

D

If you put the equation into a calculator, it will show a graph of it.

8 0
3 years ago
Does anyone know how to do this problem? If so please help so I could get it? Not only the answer but like the formula on how yo
nasty-shy [4]
Kg=1000g
0.25kg x1000g= 250g
3 0
2 years ago
a train starting from rest moves with uniform acceleration of 5 m/s2 .find its velocity when it has travelled a distance of 1 km
Degger [83]

The velocity of a train starting from rest moves with a uniform acceleration of 5 m/s2 would be 100 m/s.

Acceleration = 5 m/s2

Distance, s = 1 km = 1000m

Intital velocity, u=0 m/s

<h3>What is the first equation of motion?</h3>

We know that, Newton's equation of motion,

s = ut+ 1/2 at^2

1000 = 0 + 1/2 x 5 x t^2

1000 = 5/2 x t^2

2000/ 5 = t^2

t = 20 s

Also,a = (v-u)/t

5 = v-0/20

100 = v

v = 100 m/s

Hence, the velocity of a train starting from rest moves with a uniform acceleration of 5 m/s2 would be 100 m/s.

Learn more about velocity here;

brainly.com/question/3491339

#SPJ1

7 0
2 years ago
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