Answer:
400
Step-by-step explanation:
because if u look sideways it shows just one step up and it's 400 or it can be 500 to get 9:45
Answer:
The principal amount necessary to fund is $573.31
Step-by-step explanation:
Given as :
The quarterly withdrawal amount = A = $850
The time period for withdrawals = t = 9 years
The rate of interest = r = 4.4% compounded quarterly
Let The principal amount necessary to fund = $p
Now, <u>From Compound Interest</u>
Amount = Principal × 
Or, $850 = p × 
Or, $850 = p × 
Or, $850 = p × 
Or, $850 = p × 1.4826
∴ p = 
i.e p = $573.31
So,The principal amount necessary to fund = p = $573.31
Hence, The principal amount necessary to fund is $573.31 Answer
The polynomial functions in their expanded form is given as follows. It is right to state that there are no breaks in the domain of h(x).
<h3>
What is a polynomial function?</h3>
In an equation such as the quadratic equation, cubic equation, etc., a polynomial function is a function that only uses non-negative integer powers or only positive integer exponents of a variable.
For instance, the polynomial 3x+4 has an exponent of 1.
Part A: F(x) has zero at 2 and multiplicity of 1; and
1 at the multiplicity of 2
f(x) = x-2) (x-1)²
= (x-2) (x² - 2x + 1)
= x³ - 4x² + 5x -2
Part B: h (x) = ![\left \{ {{x^3 -4x^2 + 5x -2; X < 0} \atop {\sqrt[3]{x-2} ; X\geq 0 }} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%5E3%20-4x%5E2%20%2B%205x%20-2%3B%20X%20%3C%200%7D%20%5Catop%20%7B%5Csqrt%5B3%5D%7Bx-2%7D%20%3B%20X%5Cgeq%200%20%7D%7D%20%5Cright.)
The domain of X is X ∈ R
Hence it is correct to state that there are no breaks in the domain of h(x).
Learn more about polynomial functions:
brainly.com/question/2833285
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The formula says
I=prt
I Interest earned
P principle
R interest rate
T time
The interest earned of local account
13,670×0.019×9
=2,337.57
The interest earned of online account
6,040×0.045×9
=2,446.2
The difference
2,446.2−2,337.57
=109
So the answer is d
6(a+3) = 18 + 6a
6(a+3)=6(3+a)
a+3=3+a
a-a=3-3
0a=0
<span>B. all real numbers</span>