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Alexandra [31]
3 years ago
13

Taylor Swift wants to find the distance, AB, across a river. She starts at point B and walks along the edge of the river 94 ft a

nd marks point C. Then she walks 76 ft further and marks point D. She turns 90° and walks until her final location and marks point E. Point E, point A, and point C are collinear.

Mathematics
1 answer:
ad-work [718]3 years ago
8 0

Answer:

A) Ms. Swift can conclude that hey are similar, because line E,C,A is collinear, and they both are right triangles.

B) 158.3ft

Step-by-step explanation:

A) Having a collinear line makes the triangles similar, and because of their collinear line they are both right triangles.

B) The question tells you DE is 103 ft. You take 76ft and Square it giving you 5776ft You then take 103 and square it giving you 10609ft adding them together gives you 16385ft you take the square root of it and it gives you the hypotenuse of triangle CDE. To get the hypotenuse of triangle ABC you take The expression (AB/DE)=(BC/CD)=(AC/EC) step one (AB/DE)=(94ft/76ft)=AC/DE) step two (103ft/127ft)=(94ft/76ft)=(AC/DE) third step (103ft/127ft)=(94ft/76ft)=(128ft/158.3)

I truly hope this helps! :)

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Step-by-step explanation:

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At the Souvenir Shop, gemstone souvenirs cost $11.60 for 5. Which proportion can be used to find the cost of just 1 gemstone?
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Answer:

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6 0
2 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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