ADD = 300
ITI = 323
ON - 33 (Almost a 6 at the end!)
Answer:
32760 ways
Step-by-step explanation:
Suppose we all want to play different games, so 4 different games. At the first game there are 15 choices, at the 2nd game there are 14, the 3rd one there are 13 selections, and at the last there are only 12 options to select from. Then the total number of ways you can choose the 4 games is
15*14*13*12 = 32760 ways
X - y = 2
4x - 3y = 11.
Using Elimination method, eliminating x, multiply equation (i) by 4. Because of the 4 in the second equation.
x - y = 2 ... (x4)
4x - 3y = 11.
4x - 4y = 8
4x - 3y = 11.
The first minus the second.
(4x - 4x) -4y- -3y = 8-11
-4y + 3y = -3
-y = -3. Divide both sides by -1
y =3.
Substitute this value into the very first equation
x - y = 2, y = 3
x - 3 = 2
x = 2 + 3 = 5.
Therefore x = 5, y = 3.
Answer:
let
i= simple interest
p= principal
t= time
r=rate
data given
p=$720
r=4.25%
t= 3months
i=?
from the formula
i=prt
i=$720×(4.25/100)×3
i=$720×0.0425×3
i=$91.8
therefore simple interest for 3 months is $91.8
The difference between each number in the dollars fund is 25
209 - 184 = 25
184 - 159 = 25
so....in the ? space......134 - 25 = 109 <==