The domain of a function is the set of values for which the function is defined; i.e. the function outputs a value for an input from the domain. That means that we must be able to plug in numbers for x and get numbers from y.
We can't take the square root of negative numbers (ignoring imaginary numbers), so that means we can take the square root of any non-negative number; i.e. we can take the square root of zero, and any positive number.
Therefore, any function that can take in values of x that are zero or more than zero has the same domain as the given function. So

is a function that has the same domain as

.
Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:

Velocity:

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then

Position:

Since s(0) = 3

What is its position at time t=5?
This is s(5).



It's position at time t = 5 is 593.
Answer:
sorry I'm not in whatever grade your in
Answer:
Henry is 18 and Paul is 7
Step-by-step explanation:
I figured it out in my head.