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LiRa [457]
3 years ago
14

The Huka Falls on the Waikato River is one of New Zealand's most visited natural tourist attractions. On average, the river has

a flow rate of about 300,000 L/s. At the gorge, the river narrows to 20-m wide and averages 20-m deep.
(a) What is the average speed of the river in the gorge?
(b) What is the average speed of the water in the river downstream of the falls when it widens to 60 m and its depth increases to an average of 40 m?
Physics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

(a) V = 0.75 m/s

(b) V = 0.125 m/s

Explanation:

The speed of the flow of the river can be given by following formula:

V = Q/A

V = Q/w d

where,

V = Speed of Flow of River

Q = Volume Flow Rate of River

w = width of river

d = depth of river

A = Area of Cross-Section of River = w d

(a)

Here,

Q = (300,000 L/s)(0.001 m³/1 L) = 300 m³/s

w = 20 m

d = 20 m

Therefore,

V = (300 m³/s)/(20 m)(20 m)

<u>V = 0.75 m/s</u>

<u></u>

(b)

Here,

Q = (300,000 L/s)(0.001 m³/1 L) = 300 m³/s

w = 60 m

d = 40 m

Therefore,

V = (300 m³/s)/(60 m)(40 m)

<u>V = 0.125 m/s</u>

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An empty rubber balloon has a mass of 12.5 g. The balloon is filled with helium at a density of 0.181 kg/m3. At this density the
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Answer:

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mass of balloon (m) = 12.5 g = 0.0125 kg

density of helium = 0.181 kg/m^{3}

radius of the baloon (r) = 0.498 m

density of air = 1.29 kg/m^{3}

acceleration due to gravity (g) = 1.29 m/s^{2}

find the tension in the line

the tension in the line is the sum of all forces acting on the line

Tension =buoyant force  + force by helium + force of weight of rubber

force = mass x acceleration

from density = \frac{mass}{volume} ,  mass = density x volume

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        where density is the density of air for the buoyant force

        buoyant force = 1.29 x (\frac{4]{3} x π x 0.498^{3}) x 9.8 = 6.54 N

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        force by helium =  0.181 x (\frac{4]{3} x π x 0.498^{3}) x 9.8 = 0.917 N

  • force of its weight = mass of rubber x acceleration

        force of its weight = 0.0125 x 9.8 = 0.1225 N

  • Tension = buoyant force  + force by helium + force of weight of rubber

         the force  of weight of rubber and of helium act downwards, so they      

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3 years ago
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The kinetic energy of the crate as it reaches the lower surface is 80 J

Kinetic energy is the energy possed by an object in motion. Mathematically, the kinetic energy can be expressed as follow:

KE = ½mv²

With the above formula, the kinetic energy of the crate can be obtained as follow:

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KE = ½mv²

KE = ½ × 10 × 4²

KE = 5 × 16

KE = 80 J

Therefore, the kinetic energy of the crate is 80 J

Learn more about kinetic energy: brainly.com/question/14449170

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