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scoundrel [369]
3 years ago
15

What is the longest wavelength that can be observed in the third order for a transmission grating having 5200 slits/cm?

Physics
1 answer:
Anarel [89]3 years ago
3 0

Answer:

641 nm.

Explanation:

Given that,

A transmission grating has 5200 slits/cm.

We need to find the longest wavelength that can be observed in the third order. Using grating equation as follows :

d\sin\theta=m\lambda ...(1)

d is slit spacing

No fo slit per unit length :

N={5200}\ slit/cm\\\\=520000\ slits/m

We know that, N = 1/d

For longest wavelength, θ = 90°

From equation (1)

\dfrac{\sin\theta}{m\lambda}=\dfrac{1}{d}\\\\520000=\dfrac{\sin(90)}{3\lambda}\\\\\lambda=\dfrac{1}{520000\times 3}\\\\=6.41\times 10^{-7}\ m\\\\=641\ nm

Hence, the longest wavelength in third order for a transmission grating is 641 nm.

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a vehicle starts from rsst and after 10 seconds its velocity is 20m/s find the acceleration and the distance travelled.(step by
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Answer:

<u>Acceleration is 2 m/s² </u>

<u>Distance</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>m</u>

Explanation:

From definition of acceleration, Acceleration is the rate of change in velocity.

• Simplifying the definition, or modifying it;

{ \boxed{ \rm{acceleration =  \frac{(final \: velocity - initial \: velocity)}{time} }}}

• Let's formulate symbols:

{ \boxed{ \rm{a =  \frac{v - u}{t} }}}

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  • u is initial velocity, u = 0 m/s [ at rest ]
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{ \rm{a =  \frac{20 - 0}{10}  =  \frac{20}{10} }} \\  \\{ \boxed{ \rm{ \: a = 2 \:  {ms}^{ - 2} }}}

Distance = ut + ½at²

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3 years ago
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A resin tube and a PVC rod are both rubbed against styrofoam. Do
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The concepts of electrostatics allow us to find the result for the question about the electric forces in the two tubes is:

  • The tubes are attracted by having charges of different signs.

<h3>Electrostatics</h3>

Electrostatics studies the transfer of charge between bodies when they rub together, in generating the charges of the insulating bodies they are not mobile, so to transfer them from one body to another they must be in contact.

The force electric between charges is of two types:

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The transferred charge depends on the bodies involved in the tables showns that the resin is positively charged when rubbed, the PVC acquires very little charge and polystyrene acquires a negative charge due to rubbing.

They indicate that the resin is rubbed with polystyrene, therefore the resin must acquire a positive charge and the polystyrene a negative charge.

Then the PVC is rubbed with the polystyrene, which initially we will assume neutral, the PVC does not acquire a charge and the polystyrenes acquires a negative charge, if the polystyrene is isolated from the ground, it shares this negative charge with the PVC, therefore the two materials remain with half of the negative charge.

Finally, we bring the resin, which is positively charged, closer to the PVC, which has a slight negative charge, therefore the two bodies must attract each other.

In conclusion using the concepts of electrostatics we can find the result for the question about the electric forces in the two tubes is:

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Learn more about electrostatics here: brainly.com/question/17692887

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