Answer:
8 J and 2 J
Explanation:
Given that,
Mass of the rubber ball, m = 1 kg
Initial speed of the rubber ball, u = 4 m/s (in east)
Final speed of the rubber ball, v = -2 m/s (in west)
We need to find the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall.
Initial kinetic energy,

Final kinetic energy,

So, the initial kinetic energy is 8 J and the final kinetic energy is 2 J.
Answer:
a)
, b)
, c) 
Explanation:
a) The equation of state for ideal gas is:

Given the existence of an isothermal process, the following relation is derived:

The volume of the other tank is:



The total volume is:



b) The total mass is:



c) The pressure of the gas in the two tanks is:



First, calculate the initial velocity of the dog given with the vertical height and the acceleration due to gravity which is calculated through the equation,
2ad = Vo²
Substituting the known values,
2(9.8 m/s²)(1.2 m) = V₀²
V₀ = 4.85 m/s
The kinetic energy is solved through the equation,
KE = 0.5mv²
Substituting the known values to the latest equation,
KE = 0.5 (7.2 kg)(4.85 m/s)²
KE = 17.46 J
Thus, the kinetic energy is 17.46 J.
Answer:
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