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Umnica [9.8K]
3 years ago
5

Whenever important physicists are discussed, Galileo Galilei, Isaac Newton, and Albert Einstein seem get the most attention. How

ever, as you’ve seen, Galileo formulated or refined many of his discoveries and theories based on the findings of others who came before him, including Aristotle and Nicolaus Copernicus. Likewise, Newton claimed that he “stood on the shoulders of giants” in developing his work. You’ve just begun your study of physics, but from what you know (or can research and find out) take a position that Galileo, Newton, and Einstein deserve this special recognition. Alternately, identify a physicist that you think has been overlooked, compared to these three. Do some research and support your opinion with credible arguments
Physics
1 answer:
netineya [11]3 years ago
5 0
I'm sorry, but I don't think this question can really be answered by anyone but yourself. I would say, if you'd like some direction as to where to start, I have these suggestions:

For Galileo, I would start by researching into his experiments with gravity. Prior to him, among others, objects were thought to behave based purely on mass. He did an experiment atop the leaning tower of pisa to disprove this.

For Newton, look into how his application of calculus and formulation of the laws of motion helped to refine and complete Kepler's laws of motion.

For Einstein, look into special and general relativity, and the existence of space-time and space curvature.

For someone less recognized that might deserve more credit than they do, I would recommend Eratosthenes.

I hope this helps; happy hunting!
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A 1.0-kilogram rubber ball traveling east at 4.0 meters per second hits a wall and bounces back toward the west at 2.0 meters pe
Mrrafil [7]

Answer:

8 J and 2 J

Explanation:

Given that,

Mass of the rubber ball, m = 1 kg

Initial speed of the rubber ball, u = 4 m/s (in east)

Final speed of the rubber ball, v = -2 m/s (in west)

We need to find the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall.

Initial kinetic energy,

K_i=\dfrac{1}{2}mv^2\\\\K_i=\dfrac{1}{2}\times 1\times (4)^2\\\\K_i=8\ J

Final kinetic energy,

K_f=\dfrac{1}{2}mv^2\\\\K_f=\dfrac{1}{2}\times 1\times (2)^2\\\\K_f=2\ J

So, the initial kinetic energy is 8 J and the final kinetic energy is 2 J.

8 0
3 years ago
Which major plate will move the most over the next 500 years
crimeas [40]
A is the correct answer
8 0
3 years ago
A 5 m3 tank containing 5kg of an unknown ideal gas at 500 kPa is connected through a valve to another tank containing 10 kg of t
Ivan

Answer:

a) V_{T} = 9\,m^{2}, b) m_{T} = 15\,kg, c) P_{T} = 416.667\,kPa

Explanation:

a) The equation of state for ideal gas is:

P \cdot V = \frac{m}{M}\cdot R_{u}\cdot T

Given the existence of an isothermal process, the following relation is derived:

\frac{P_{1}\cdot V_{1}}{m_{1}} = \frac{P_{2}\cdot V_{2}}{m_{2}}

The volume of the other tank is:

V_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}}\right)\cdot V_{1}

V_{2} = \left(\frac{10\,kg}{5\,kg} \right)\cdot \left(\frac{200\,kPa}{500\,kPa}\right)\cdot (5\,m^{3})

V_{2} = 4\,m^{3}

The total volume is:

V_{T} = V_{1} + V_{2}

V_{T} = 5\,m^{3} + 4\,m^{3}

V_{T} = 9\,m^{2}

b) The total mass is:

m_{T} = m_{1} + m_{2}

m_{T} = 5\,kg + 10\,kg

m_{T} = 15\,kg

c) The pressure of the gas in the two tanks is:

P_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{V_{1}}{V_{2}}\right)\cdot P_{1}

P_{T} = \left(\frac{15\,kg}{5\,kg}\right)\cdot \left(\frac{5\,m^{2}}{9\,m^{2}} \right)\cdot (500\,kPa)

P_{T} = 416.667\,kPa

3 0
4 years ago
How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m?(gravity is 9.8)
Mekhanik [1.2K]
First, calculate the initial velocity of the dog given with the vertical height and the acceleration due to gravity which is calculated through the equation,
                         2ad = Vo²
Substituting the known values,
                           2(9.8 m/s²)(1.2 m) = V₀²
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The kinetic energy is solved through the equation, 
                         KE = 0.5mv²
Substituting the known values to the latest equation,
                         KE = 0.5 (7.2 kg)(4.85 m/s)²
                          KE = 17.46 J
Thus, the kinetic energy is 17.46 J. 
8 0
3 years ago
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Answer:

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