<u>Answer:</u> The volume of barium chlorate is 195.65 mL
<u>Explanation:</u>
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
Given mass of barium chlorate = 25.0 g
Molar mass of barium chlorate = 304.23 g/mol
Molarity of solution = 0.420 mol/L
Volume of solution = ?
Putting values in above equation, we get:
Hence, the volume of barium chlorate is 195.65 mL
Answer:
0.0006 mole
Explanation:
Considering:
Or,
Given :
For HCl :
Molarity = 0.100 M
Volume = 6.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 6.0×10⁻³ L
Thus, moles of potassium iodide :
Moles of HCl = 0.0006 moles
From the reaction shown below:-
1 mole of HCl reacts with 1 mole of sodium carbonate.
So,
0.0006 mole of HCl reacts with 0.0006 mole of sodium carbonate.
<u>Moles of sodium carbonate = 0.0006 moles</u>