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rjkz [21]
4 years ago
9

Lewis dot structure KOH

Chemistry
1 answer:
svetlana [45]4 years ago
6 0
? What??????? You need help or what
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What is the oxidized substance in the following reaction? <br><br> Fe + 2HCl → FeCl2 + H2
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4 0
3 years ago
How many total ions are present in 347g of cacl2?
vladimir1956 [14]

In 1 mole of CaCl_{2}, there are 3 moles of ions, 1 mole of Ca^{2+} and 2 mole of Cl^{-1}.

CaCl_{2}\rightarrow Ca^{2+}+2Cl^{-}

Molar mass of CaCl_{2} is 110.98 g/mol. Calculating number of moles from given mass as follows:

n=\frac{m}{M}=\frac{347 g}{110.98 g/mol}=3.12 mol

Thus, number of moles of ions will be 3\times 3.12 mol=9.38 mol.

Since, 1 mole of any substance has 6.023\times 10^{23} units of that substance where 6.023\times 10^{23}  is Avogadro's number.

Thus, 9.38 mol of ions will have 9.38\times 6.023\times 10^{23}=5.65\times 10^{24} number of ions.

Therefore, total number of ions in 347 g of CaCl_{2} is  5.65\times 10^{24}.


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