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Rina8888 [55]
2 years ago
9

Vaporized water is also known as

Chemistry
1 answer:
viva [34]2 years ago
4 0

Answer:

fog

Explanation:

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A specific steroid has a λmax of 257 nm and a molar absorptivity ε of 11 , 500 L mol − 1 cm − 1 . What is the concentration of t
joja [24]

Answer:

7.83\times 10^{-6} M is the concentration of the compound in a solution.

Explanation:

Using Beer-Lambert's law :

Formula used :

A=\epsilon \times C\times l

Where:

A = absorbance of solution

C = concentration of solution

l = path length

\epsilon = molar absorptivity coefficient

We have:

C = ? , l = 1.00 cm, A = 0.090

\epsilon = 11,500 L/(mol cm)

C=\frac{A}{\epsilon l}=\frac{0.090}{11,500 L/(mol cm)\times 1.00 cm}

C=7.83\times 10^{-6} M

7.83\times 10^{-6} M is the concentration of the compound in a solution.

6 0
3 years ago
Write a Balanced Equation <br><br><br><br> H2 + Cl2 --&gt; __HCl
Mariana [72]

Answer:

2HCL

Explanation:

Both the elements have 2 so when placing the 2 infront ,it'll distribute/ apply to both

7 0
2 years ago
What are the reaction types for the following?
Bingel [31]

Answer:

1. decomposition

2. combustion

3.single replacement

4. combination

5. double replacement

Explanation:

1. one compound is split into 2 elements

2. co2 and h20 was the product of the reaction

3. cu is replaced with co

4. 2 compounds become one compound

5. ca is replaced with na and na is replaced with ca

6 0
3 years ago
__________ is a condition in which water droplets in air do not freeze even when the air cools below the freezing point.
IrinaK [193]
The answer is: <span>supersaturation</span>
7 0
2 years ago
The combustion of caffeine with the molecular masses is given below. If you have 0.150 grams of caffeine, how much NO2 in grams
lord [1]

Answer:

1. 0.14 g of NO2.

2. 0.27 g of CO2.

Explanation:

The balanced equation for the reaction is given below:

2C8H10N4O2 + 27O2 —> 16CO2 + 10H2O + 8NO2

Next, we shall determine the mass of caffeine, C8H10N4O2 that reacted and the masses of nitrogen (iv) oxide, NO2 and carbon (iv) oxide, CO2 produced from the balanced equation. This can be obtained as follow:

Molar mass of of C8H10N4O2 = 194.19 g/mol

Mass of C8H10N4O2 from the balanced equation = 2 × 194.19 = 388.38 g

Molar mass of CO2 = 44.01 g/mol

Mass of CO2 from the balanced equation = 16 × 44.01 = 704.16 g

Molar mass of NO2 = 46.01 g/mol

Mass of NO2 from the balanced equation = 8 × 46.01 = 368.08 g

Summary:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2 and 368.08 g of NO2.

1. Determination of the mass of NO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 368.08 g of NO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 368.08) / 388.38 = 0.14 g of NO2.

Therefore, 0.14 g of NO2 was obtained from the reaction.

2. Determination of the mass of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 704.16) / 388.38 = 0.27 g of CO2.

Therefore, 0.27 g of CO2 was obtained from the reaction.

8 0
2 years ago
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