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Andrei [34K]
3 years ago
13

What is the radius of a circle whose equation is x^2+y^2-10x+6y + 18=0

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

Explanation:

We must write this equation in the form

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

Where

(

a

,

b

)

are the co ordinates of the center of the circle and the radius is

r

.

So the equation is

x

2

+

y

2

−

10

x

+

6

y

+

18

=

0

Complete the squares so add 25 on both sides of the equation

x

2

+

y

2

−

10

x

+

25

+

6

y

+

18

=

0

+

25

=

(

x

−

5

)

2

+

y

2

+

6

y

+

18

=

0

+

25

Now add 9 on both sides

(

x

−

5

)

2

+

y

2

+

6

y

+

18

+

9

=

0

+

25

+

9

=

(

x

−

5

)

2

+

(

y

+

3

)

2

+

18

=

0

+

25

+

9

This becomes

(

x

−

5

)

2

+

(

y

+

3

)

2

=

16

So we can see that the centre is

(

5

,

−

3

)

and the radius is

√

16

or 4

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Answer:

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Step-by-step explanation:

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Evaluate C(44,21) use scientific notation, round to 3 decimal places as needed.
STALIN [3.7K]
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baherus [9]
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Alja [10]

Answer:

Step-by-step explanation:

Isn’t this mathematics not science

4 0
3 years ago
-5= s<br> —<br> 18<br> Someone help please I’m stuck
Vlad1618 [11]

-5=s/18

Pretend that s/18 is 1/18s

-5=1/18s

Multiply by 18/1 for both sides

-5(18/1)=1/18(18/1)s

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