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stiks02 [169]
3 years ago
7

How do I move one side to the other:

n%5E2%5Calpha%20-%201" id="TexFormula1" title="sin^2\alpha - cos^2\alpha = 2sin^2\alpha - 1" alt="sin^2\alpha - cos^2\alpha = 2sin^2\alpha - 1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

9514 1404 393

Explanation:

You can use the addition property of equality to "move" a term from one side of the equation to the other. For example, if you want to move the cos²α term, you can add cos²α to both sides of the equation:

  sin²α -cos²α +cos²α = 2sin²α -1 +cos²α

When this is simplified, it becomes ...

  sin²α = 2sin²α +cos²α -1 . . . . . . the cos²α term is gone from the left

__

The equation you have is an identity. The left and right sides are equal for any value of α. When you have such an equation as a trig problem, you are often being asked to prove it is true. The way you do that is to make use of other trig identities to transform one side so that it matches the other side.

Here, you can use the trig identity ...

  sin²α +cos²α = 1

If you use this to substitute for 1 on the right, you have ...

  sin²α - cos²α = 2sin²α - (sin²α +cos²α)

Now, when you collect terms, you get ...

  sin²α - cos²α = 2sin²α - sin²α -cos²α . . . eliminate parentheses

  sin²α - cos²α = sin²α - cos²α . . . . . proof of your identity

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Someone please help meeeee
zepelin [54]

Answer:

The number is -1

Step-by-step explanation:

The equation for the first part is (2n+7)2. This is because "twice a number" is 2n and "7 is added" will make it 2n+7. The "sum is multiplied by two" Is multiplying everything by two. This will make it (2n+7)

The second part is  -8n+2. Since a number is multiplied by negative eight it will be -8n. Then it is added by two.

Both equation equal each other the overall equation will be (2n+7)2=-8n+2

You will distribute. making it 4n+14=-8n+2

Add 8n to both sides making it 12n+14=2

subtract 14 from both sides making it 12n=-12

Divide both sides by 12 . making it number=-1

4 0
3 years ago
Which is a composite number A. 81 B. 41 C. 61 D. 71
UNO [17]
A,81 because if you try checking 81 will be the only composite number im in 6 grade.....

6 0
3 years ago
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If I have 500 animals and gave away 267 how much would I have left
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Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

⇒ \frac{15}{Sin 29} = \frac{20}{sin B}

Using value of sin 29°

⇒ \frac{15}{0.49} = \frac{20}{sin B}

Cross multiplying both side.

⇒ Sin B= \frac{20\times 0.49}{15} = 0.65

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ 29+41+B= 180

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

7 0
3 years ago
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Answer:

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