Answer:
P = 0.5Q - 20
Step-by-step explanation:
P = kQ + c
substitute Q = 60 , P = 10 into the equation
10 = 60k + c → (1)
substitute Q = 240, P = 100 into the equation
100 = 240k + c → (2)
subtract (1) from (2) term by term to eliminate c
90 = 180k ( divide both sides by 180 )
=
= 0.5 = k
substitute k = 0.5 into (1) and solve for c
10 = 60(0.5) + c
10 = 30 + c ( subtract 30 from both sides )
- 20 = c
then
P = 0.5Q - 20
Answer:
A. O 5
Step-by-step explanation:
1830 ÷ 31 = 59.032258...
The first non-zero digit of the quotient is 5.
Answer:
To solve the system below by substitution, replace y in the second equation with 7−6x.
==> False
This statement is false. To solve the system by substitution, replace x in the second equation with 7−6x.
==> False.
This statement is false. To solve the system by substitution, replace y in the first equation with 7−6x.
==> False
This statement is false. To solve the system by substitution, replace y in the second equation with 6x−7.
==> True.
<em>From</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>equat</em><em>ion</em><em>,</em><em> </em><em>6</em><em>x</em><em>-</em><em>y</em><em>=</em><em>7</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>y</em><em>=</em><em> </em><em>6</em><em>x</em><em>-</em><em>7</em>
Answer:
1 + i
Step-by-step explanation:
To rationalize multiply numerator and denominator by (2 + i )
