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WINSTONCH [101]
3 years ago
8

A triangle with area 40 square inches has a height that is four less than six times the base. Find the base and height of the tr

iangle
Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

A = 1/2bh

Step-by-step explanation:

40 = (.5)(6x - 4)(x)

40 = (3x-2)(x)

40= 3x^2 - 2x

3x^2 -2x - 40 =0

3x^2 - 12x + 10x - 40 = 0

3x(x - 4) + 10(x -4) = 0

(3x + 10)(x - 4) = 0

x = {4 , - 10/3}

x = 4 , b = 20. h = 4

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olasank [31]

Dilation by a scale factor of 1/2 followed by a translation of 1.5 units down.

<h3>What is dilation?</h3>

Dilation is a transformation, which is used to resize the object. Dilation is used to make the objects larger or smaller.

Here, △ HIJ are:

IH = 3

IJ = 4

then using the scale factor = 1/2 we get

Therefore, we have:

I'H '= 1.5

I'J '= 2

Hence, dilation by a scale factor of 1/2 followed by a translation of 1.5 units down.

Learn more about this concept here:

brainly.com/question/1011146

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2 years ago
Brainliest!!!
Cloud [144]

Answer:

3rd option

Step-by-step explanation:

We have two kind of necks and three different colours so the andswer would be 3rd option

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3 years ago
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I need to know the answer to this?
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Answer:

5 min person wit 10 min person

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5 0
3 years ago
The image of the polygon ABCDE reflected across the x-axis. A(-1,-1),B(0,1),C(4,2),D(6,0),E(3,-3) The vertices of the image are.
4vir4ik [10]

A reflection across the x-axis has the rule:

(x,y)→(x,-y).

Then:

  • A(-1,-1)→A'(-1,1),
  • B(0,1)→B'(0,-1),
  • C(4,2)→C'(4,-2),
  • D(6,0)→D'(6,0),
  • E(3,-3)→E'(3,3).

Answer: the vertices of the image are A'(-1,1), B'(0,-1), C'(4,-2), D'(6,0) and E'(3,3).

6 0
3 years ago
F(x) = 49 − x2 from x = 1 to x = 7; 4 subintervals
Setler [38]

Answe

Given,

f(x) = 49 − x² from x = 1 to x = 7

n = 4

\Delta x = \dfrac{7-1}{4}= 1.5

For x= 1

f(x₀) = 49 - 1^2 = 48

x = 2.5

f(x₁) = 42.75

x = 4

f(x₂) = 49 - 4^2 = 33

x = 5.5

f(x₃) = 49 - 5.5^2 = 18.75

x = 7

f(x₄) = 49 - 7^2 = 0

We have to evaluate the function on therigh hand point

A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]

A = 1.5 [42.75+33+18.75+0]

A = 141.75

For Area for left hand sum

A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]

A = 1.5 [48+42.75+33+18.75]

A =213.75

3 0
3 years ago
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