All categories

2 years ago

Is there a easy way to subtract fractions with unlike deiomaters

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

8 0

Answer:

Yes

Step-by-step explanation:

It's just like adding fractions where you have to find the common denominator so the fractions can be subtracted.

<u>Example</u>

<u /> $\displaystyle \frac{1}{2}-\frac{1}{3}=\frac{1*3}{2*3}-\frac{2*1}{2*3}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}$

You might be interested in

If a(x) and b(x) are linear functions with one variable, which of the following expressions produces a quadratic function?

horrorfan [7]

Hi,

the answer is A. (ab)(x)

8 0

2 years ago

Read 2 more answers

Please help I think its 16 but not sure

Stels [109]

Answer:

I think its 12 to this question

6 0

2 years ago

Pls help for this pre calc question 25 points rewarded!

Temka [501]

Let's check the dot product .

v.w = 5(4)-2(10) = 20 -20 =0

So the dot product is not 20 . And since the dot product is zero, so they are perpendicular.

And the y component of w is 10.

So correct options are first and third .

3 0

3 years ago

Can you write the standard form of the line that contains a slope of 1/2 and y-intercept of 3?

slavikrds [6]

Standard form is ax+by=c
normally a is positive and a and b are integres
y=mx+b
m=slope
b=yint
y=1/2x+3
minus 1/2 x both sides
-1/2x+y=3
times -2
x-2y=-6

8 0

2 years ago

NEED HELP WITH THIS PROBLEM!!!!!!

zzz [600]

Answer:

$\displaystyle\frac{\sqrt[4]{3x^2}}{2y}$

Step-by-step explanation:

It can work well to identify 4th powers under the radical, then remove them.

$\displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}$

_____

The applicable rules of exponents are ...

1/a^b = a^-b

(a^b)(a^c) = a^(b+c)

The x-factors simplify as ...

x^6/x^4 = x^(6-4) = x^2

The y-factors simplify as ...

y/y^5 = 1/y^(5-1) = 1/y^4

The constant factors simplify in the usual way:

24/128 = (8·3)/(8·16) = 3/16

3 0

3 years ago