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zepelin [54]
3 years ago
14

The main benefit you receive from using locomotor movements in a variety of activities is? Question 3 options:

Physics
2 answers:
Naily [24]3 years ago
8 0

Answer:

I think the answer is Improve agility

Explanation:

Helga [31]3 years ago
4 0

Answer:

run walk jump digk pwss botch

Explanation:

fudge

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What does the term "speed" describe?
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The cyclist who travels 20 kilometers per hour for 15 kilometers
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What is an equilibrant?
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7 0
3 years ago
Read 2 more answers
The end of an action movie car chase involves the villain driving off a vertical cliff and falling into the ocean below You have
AnnyKZ [126]

Answer:

The initial velocity should be greater than 23.9 m/s. This velocity is underestimated because it does not take into account the resistance of the air.

Explanation:

Hi there!

The final position vector of the car (denoted as "r" in the figure) is

r = ( 120, -100) m

(placing the origin of the frame of reference at the launching point).

The position vector at a time "t" is calculated by the following equation:

r = (x0 + v0 · t · cos θ, y0 + v0 · t · sin θ + 1/2 · g · t²)

Where:

x0 = initial vertical position.

v0 = initial velocity.

t = time.

θ = launching angle.

y0 = initial vertical position.

g = acceleration due to gravity.

At final time:

120 m = x0 + v0 · t · cos θ

-100 m = y0 + v0 · t · sin θ + 1/2 · g · t²

Since the origin is placed at the launching point, x0 and y0 = 0, then:

120 m = v0 · t · cos θ

-100 m = v0 · t · sin θ + 1/2 · g · t²  

We have a system with two equations and two unknowns, so, we can solve it.

Solving the first equation for "v0":

120 m = v0 · t · cos θ

v0 = 120 m / (cos θ · t)

Replacing v0 in the second equation:

-100 m = v0 · t · sin θ + 1/2 · g · t²  

-100 m = (120 m/cos 15° · t) · t · sin 15° - 1/2 · (9.8 m/s²) · t²  

-100 m = 120 m · tan 15° - 4.9 m/s² · t²

(-100 m - 120 m · tan 15°) / (-4.9 m/s²) = t²

t = 5.2 s

Now we can calculate the initial velocity:

v0 = 120 m / cos 15° · 5.2 s

v0 = 23.9 m/s

The initial velocity should be greater than 23.9 m/s

This velocity is underestimated because it does not take into account the resistance of the air.

8 0
3 years ago
If a motorcycle moves with a constant velocity, can you conclude that there is no net force acting on it?
Reil [10]
Answer:  Yes

Explanation:
Newton's Law of motion is
F = ma
where F = force,
m =mass,
a = acceleration.

Because the motorcycle moves with a constant velocity, the acceleration is zero, and there is no net force.

Although there is no net force, there are many forces that are in equilibrium.
(i) There is the driving force that is provided by the engine,
(ii) There is wind resistance,
(ii) There is frictional resistance.

At constant velocity, the sum of resistive forces is equal to the driving force.
5 0
3 years ago
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