Answer:
Fm = 51N and Fj = 26N
Summing the moments about the shoulder joint
Sum of anticlockwise moments = sum of clockwise moments
Fm x 12 = mg x 24
Fm = 2.6 x 9.8 × 24/12
Fm = 51N
Summing the forces acting on the arm
Sum of upward forces = sum of downward forces
Fm = Fj + mg
51 = Fj + 2.6 × 9.8
51 = Fj + 25.48
Fj = 51 - 25.48
Fj = 26N
Explanation:
Newtons first law and the principle of moments have been applied in solving this problem.
Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1) 
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2) 
Solving for time t:

(3) 
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4) 
Solving equation 4 for acceleration of rocket B:
(5) 
Answer:
ik u got it bc this was 2 weeks ago
Explanation:
but yes and yuea
To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.
Our values are given as


The angular velocity of a body can be described as a function of frequency as



PART A) The expression for the maximum angular velocity is given by the amplitude so that



PART B) The maximum acceleration on your part would be given by the expression



Its 1.0*10^-7M its considered a concentration because hydrogen ion is exactly equal to hydroxide ions produced by dissociation of water