The temperature of the water and copper beaker be together is 29.6⁰C.
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What is the equilibrium temperature of both substance?</h3>
The final temperature or equilibrium temperature of the water and copper beaker is calculated by applying the principle of conservation of energy.
Heat lost by the water = Heat gained by the copper beaker
mcΔθ (water) = mcΔθ (copper)
where;
- m is mass
- c is specific heat capacity
- Δθ is change in temperature
m₁c₁(T₁ - T) = m₂c₂(T - T₂)
where;
- T₁ is the initial temperature of water
- T₂ is the initial temperature of copper beaker
- T is the equilibrium temperature
Specific heat capacity of copper, c₂ = 389 J/kgK
Specific heat capacity of water , c₁ = 4200 J/kgK
(2)(4200)(30 - T) = (1)(389)(T - 20)
252,000 - 8400T = 389T - 7780
259,780 = 8789T
T = 259,780 /8789
T = 29.6⁰C
Learn more about equilibrium temperature here: brainly.com/question/8925446
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