All categories

1 year ago

2kg of water at 30 C is poured into a 1kg copper beaker at 20 C.

Physics

1 answer:

GREYUIT [131]1 year ago

8 0

The temperature of the water and copper beaker be together is 29.6⁰C.

<h3>What is the equilibrium temperature of both substance?</h3>

The final temperature or equilibrium temperature of the water and copper beaker is calculated by applying the principle of conservation of energy.

Heat lost by the water = Heat gained by the copper beaker

mcΔθ (water) = mcΔθ (copper)

where;

m is mass
c is specific heat capacity
Δθ is change in temperature

m₁c₁(T₁ - T) = m₂c₂(T - T₂)

where;

T₁ is the initial temperature of water
T₂ is the initial temperature of copper beaker
T is the equilibrium temperature

Specific heat capacity of copper, c₂ = 389 J/kgK

Specific heat capacity of water , c₁ = 4200 J/kgK

(2)(4200)(30 - T) = (1)(389)(T - 20)

252,000 - 8400T = 389T - 7780

259,780 = 8789T

T = 259,780 /8789

T = 29.6⁰C

Learn more about equilibrium temperature here: brainly.com/question/8925446

#SPJ1

You might be interested in

What type of wave passes through the spring in the frog toy? Why?

Setler [38]

Is the Frog Toy a piece of literature? If so, the type of wave is the "Wave of Life." Spring brings new life and a new start from the harsh winter.

8 0

3 years ago

PLEASE HURRYYYY!!!<br><br> Explain how you read measurements in a graduated cylinder?

fredd [130]

Answer:

Reading a Graduated Cylinder

Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.....

hope it helps....

5 0

1 year ago

What are the Rules of magnetism

Keith_Richards [23]

all the allials must be aligned in the same direction

magnets are affected by heat, drops, and improper storage

3 0

3 years ago

6. Convert -180° to radians

icang [17]

Answer:

-3.141593

Explanation:

3 0

3 years ago

Read 2 more answers

A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the pendulum is take

Juli2301 [7.4K]

To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:

$T =2\pi \sqrt{\frac{L}{g}}$

Here,

L = Length

g = Acceleration due to gravity

We can realize that $2 \pi$ is a constant so it is proportional to the square root of its length over its gravity,

$T \propto \sqrt{\frac{L}{g}}$

Since the body is in constant free fall, that is, a point where gravity tends to be zero:

$g \rightarrow 0 \Rightarrow T \rightarrow \infty$

The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.

5 0

3 years ago