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ladessa [460]
3 years ago
9

Which describes an atom that has fewer neutrons than protons and more electrons than protons?

Physics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

negative ion

Explanation:

An atom that has fewer neutrons than protons and more electrons than protons is a negative ion.

The positively charged particles in an atom are the protons

The negatively charged particles in an atom are the electrons.

  The charge an atom carries depends on the balance between the number of protons and electrons in an atom.

  • When the number of protons is more than the number of electrons, the atom is positively charged.
  • When the number of electrons is more than the number of protons, the atom is negatively charged.
Naily [24]3 years ago
7 0

negative ion

Explanation:

An atom that has fewer neutrons than protons and more electrons than protons is a negative ion.

The positively charged particles in an atom are the protons

The negatively charged particles in an atom are the electrons.

 The charge an atom carries depends on the balance between the number of protons and electrons in an atom.

When the number of protons is more than the number of electrons, the atom is positively charged.

When the number of electrons is more than the number of protons, the atom is negatively charged.

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4 years ago
Block m1 of mass 2m and velocity v0 is traveling to the right (+x) and makes an elastic head-on collision with block m2 of mass
Oksana_A [137]
1) In any collision the momentum is conserved

(2*m)*(vo) + (m)*(-2*vo) = (2*m)(v1') + (m)(v2')

candel all the m factors (because they appear in all the terms on both sides of the equation)

2(vo) - 2(vo) = 2(v1') + (v2') => 2(v1') + v(2') = 0 => (v2') = - 2(v1')

2) Elastic collision => conservation of energy

=> [1/2] (2*m) (vo)^2 + [1/2](m)*(2*vo)^2 = [1/2](2*m)(v1')^2 + [1/2](m)(v2')^2

cancel all the 1/2 and m factors =>

2(vo)^2 + 4(vo)^2 = 2(v1')^2 + (v2')^2 =>

4(vo)^2 = 2(v1')^2 + (v2')^2

now replace (v2') = -2(v1')

=> 4(vo)^2 = 2(v1')^2 + [-2(v1')]^2 = 2(v1')^2 + 4(v1')^2 = 6(v1')^2 =>

(v1')^2 = [4/6] (vo)^2 =>

(v1')^2 = [2/3] (vo)^2 =>

(v1') = [√(2/3)]*(vo)

Answer: (v1') = [√(2/3)]*(vo)




 
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3 years ago
To understand the meaning and possible applications of the work-energy theorem.
rosijanka [135]

Answer:

   <u> a = V final 2___v initial2</u>

                      28

Explanation:

By definition for contant acceleration        <u>a =   V final ___v initial</u>

                                                                                      t

Furthermore the average speed is           <u>V abg =  v initial +v final</u>

                                                                                         2

Combine these relationships to eliminate t.               8 = Vabg t.

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3 years ago
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