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3 years ago

Which describes an atom that has fewer neutrons than protons and more electrons than protons?

Physics

2 answers:

aleksklad [387]3 years ago

7 0

Answer:

negative ion

Explanation:

An atom that has fewer neutrons than protons and more electrons than protons is a negative ion.

The positively charged particles in an atom are the protons

The negatively charged particles in an atom are the electrons.

The charge an atom carries depends on the balance between the number of protons and electrons in an atom.

When the number of protons is more than the number of electrons, the atom is positively charged.
When the number of electrons is more than the number of protons, the atom is negatively charged.

Naily [24]3 years ago

7 0

negative ion

Explanation:

An atom that has fewer neutrons than protons and more electrons than protons is a negative ion.

The positively charged particles in an atom are the protons

The negatively charged particles in an atom are the electrons.

The charge an atom carries depends on the balance between the number of protons and electrons in an atom.

When the number of protons is more than the number of electrons, the atom is positively charged.

When the number of electrons is more than the number of protons, the atom is negatively charged.

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BARSIC [14]

Answer:

$v_A=7667m/s\\\\v_B=7487m/s$

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

$F_g=\frac{GMm}{R^{2} }$

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

$F_c=m\frac{v^{2}}{R}$

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

$\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}$

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So $R_A=6774km=6.774*10^6m$ and $R_B=7103km=7.103*10^6m$ (Since $R_{earth}=6371km$ ). Then, we get:

$v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s$

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

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3 years ago