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Sunny_sXe [5.5K]
3 years ago
5

Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
2 answers:
Contact [7]3 years ago
8 0

Answer:

e,e,e,e,e,e,e,e,e,,e,e,eeeeeeeeeeeeeeeee

Step-by-step explanation:

e=e2 x e/2

harkovskaia [24]3 years ago
6 0

Answer:

EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Step-by-step explanation:

REEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

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Find the Slope of lines passing through the points: (4,5) and (6,7)​
kupik [55]

the answer is 0.6 you gotta divide and multiply

4 0
3 years ago
List all the factors of the composite number 146
Temka [501]
1 and 146
2 and 73
and that's about it
6 0
4 years ago
The coffee counter charges ?"$11.00" per pound for kenyan french roast coffee and ?"$13.00" per pound for sumatra coffee. How mu
zloy xaker [14]

Answer: The answer is 13 ponds of each type should be used.

Step-by-step explanation:  Given that the coffee counter charges $11.00 per pound for kenyan french roast coffee and $13.00 per pound for sumatra coffee. We are to find the quantity of each type that should be used to make a 26 pound blend that sells for $12.00 per pound.

Let 'x' pound and 'y' pound of  kenyan french roast coffee and sumatra coffee be used in the mixture of 26 pound.

So, we have

x+y=26,~~~~~~~~~~~~~~~~~~~~~~(A)\\\\11x+13y=12\times 26.~~~~~~~~~~(B)

Multiplying equation (A) by 11 and subtracting from equation (B), we have

13y-11y=12\times26-11\times26\\\\\Rightarrow 2y=26\\\\\Rightarrow y=13,

and from equation (A),

x=26-13=13.

Thus, 13 pounds of each type of coffee should be used.

8 0
3 years ago
Dana walks 3/4 miles in 1/4 hours. What is dana's walking rate in miles per hour?
Harman [31]

Dana’s waking rate in miles per hour is 3 mph.

I did 3/4 x 4 = 3 because she walked 1/4 a mile and I needed to figure out the miles per one whole hour.

I hope this made sense and helped you.

5 0
3 years ago
Read 2 more answers
I need help with this question
Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

$ \frac{-(\sqrt{3} + 1)}{2\sqrt{2}} $

$ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $

Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

(A) $ sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4}  + \frac{\pi}{6}) $

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}

(B) Cos(A + B) = CosAcosB - SinASinB

$ cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}}) $

$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

$ \implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}) $

$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}

(C) Tan(A + B) = $ \frac{Sin(A +B)}{Cos(A + B)} $

From the above obtained values this can be calculated and the value is $ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $.

3 0
3 years ago
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