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2 years ago

Find the range and interquartile range (IQR) of the data set in the box plot.

Mathematics

1 answer:

Eduardwww [97]2 years ago

6 0

Answer:

Range = 23

IQR= 14.5

Step-by-step explanation:

Range is the biggest number- smallest number

so 30-7=23

IQR - Interquartile range = upper quartile - lower quartile

24-9.5=14.5

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What is 2√47. please help me. I need this ASAP

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Answer:

13.7113092008

Step-by-step explanation:

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2 years ago

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In science class the students were asked to create a container to hold an egg. They would then drop the container from a window

belka [17]

Answer:

It will take 1.25 seconds to reach the ground.

Step-by-step explanation:

The equation of the containers pathway can be modeled by the equation given below :

$h=-16t^2+25$

t is time in seconds

It is required to find the time taken by the container to reach the ground. When it reached ground, its height is equal to 0 such that,

$h=0\\\\-16t^2+25=0$

$-16t^2=25\\\\t=\sqrt{\dfrac{25}{16}} \\\\t=1.25\ s$

So, it will take 1.25 seconds to reach the ground.

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3 years ago

(HELP PLS) A triangle has the coordinates

kari74 [83]

A(-4, -1)
B(-3, -3)
C(0, 2)

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3 years ago

Fast forward to the moment after the two outermost recursive calls complete, but before the final Merge step. Thinking of the tw

adoni [48]

Answer:

The answer is 2.

Step-by-step explanation:

1- Suppose we have following array of ten integers: 5 3 8 9 1 7 0 2 6 4.

2- Before the last merge, the left half and the right half must be sorted. So it should be

1 3 5 8 9 0 2 4 6 7

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3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

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2 years ago