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3 years ago

Can someone help me?

Chemistry

1 answer:

Maksim231197 [3]3 years ago

3 0

Answer:

Itz 4 and watch the superbowl please.

Explanation:

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An economical substitute for vitreous silica is a high-silica glass made by leaching the B2O3-rich phase from a two-phase borosi

stich3 [128]

Answer:48kg of SiO2, 0.5kg of Al2O3, and 1.5kg of B2O3

Will be the final product

Explanation:

I) 96wt% of SiO2 will amount to 96/100*50 = 0.96*50=48kg of SiO2

ii) 1wt% of Al2O3 will amount to 1/100*50 = 0.01*50=0.5kg of Al2O3

III) 3wt% of B2O3 will amount to 3/100*50 = 0.03*50=1.5kg of B2O3..

The overall product form 48+ 0.5+1.5= 50kg

7 0

3 years ago

45.3 in. to millimeters

Stels [109]

1,150.62 millimeters

8 0

3 years ago

What does the amount of kinetic energy an object has depend on?

Nastasia [14]

The answer is Velocity and potential energy. Kinetic energy is the total energy of a system or an object in motion and requires movement.

6 0

3 years ago

You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p

Elenna [48]

Answer:

<u>1.29 mol</u>

Explanation:

This is a direct application of the equation for ideal gases.

$PV=nRT$

Where:

P = pressure = 1.25 atm
V = volume = 25.2 liter
R = Universal constant of gases = 0.08206 atm-liter/K-mol
T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
n = number of moles

Solving for n:

$n=\frac{PV}{RT}$

Substituting:

$n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol$

8 0

3 years ago

A buret is filled with 0.1517 M naoh A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer

antiseptic1488 [7]

Answer:

molarity of acid =0.0132 M

Explanation:

We are considering that the unknown acid is monoprotic. Let the acid is HA.

The reaction between NaOH and acid will be:

$NaOH+HA--->NaA+H_{2}O$

Thus one mole of acid will react with one mole of base.

The moles of base reacted = molarity of NaOH X volume of NaOH

The volume of NaOH used = Final burette reading - Initial reading

Volume of NaOH used = 22.50-0.55= 21.95 mL

Moles of NaOH = 0.1517X21.95=3.33 mmole

The moles of acid reacted = 3.33 mmole

The molarity of acid will be = $\frac{mmole}{volumne(mL)}=\frac{0.33}{25}=0.0132M$

4 0

3 years ago

Can someone help me?​

Can someone help me?