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Lostsunrise [7]
3 years ago
8

Can someone help me?​

Chemistry
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer:

Itz 4 and watch the superbowl please.

Explanation:

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Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M
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The value of equilibrium constant is equal to the quotient of the products raised to its stoichiometric coefficient over the reaction's reactants raised to its respective stoichiometric coeff. The equation is Kc=[SO2][Cl2]/[SO2Cl2]= [1.3*10^-2][1.3*10^-2]/[2.2*10^-2-<span>1.3*10^-2]=0.0188. The final answer is Kc=0.0188.</span>
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How would you compare Uranus (a Jovian planet) to Earth (a terrestrial planet)?
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Uranus is much bigger than Earth.
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it’s about four times bigger than the watch, Uranus is about 31,000 miles in diameter while the earth is only about 7,900 miles.
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How does the periodic table help us to predict unknown elements?
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What law is the relationship between the volume and temperature of a gas is often referred to as​
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7 0
3 years ago
100. mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution
PolarNik [594]

<u>Answer:</u> The molar mass of the unknown protein is 6387.9 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 0.0766 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of protein = 100. mg = 0.100 g   (Conversion factor:  1 g = 1000 mg)

Molar mass of protein = ?

Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

0.0766atm=1\times \frac{0.100\times 1000}{\text{Molar mass of protein}\times 5}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\\pi=\frac{1\times 0.100\times 1000\times 0.0821\times 298}{0.0766\times 5}=6387.9g/mol

Hence, the molar mass of the unknown protein is 6387.9 g/mol

5 0
4 years ago
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