Can u send me the link ? Sorry tho but I don’t know how to go to ur questions :(
He disproved that living cells come from non living things
Answer:
93.15 %
Explanation:
We have to start with the chemical reaction:
Now, we can balance the reaction:
Our initial data are the 15.71 g of 
, so we have to do the following steps:
1) <u>Convert from grams to moles of using the molar mass (110.98 g/mol).</u>
2) <u>Convert from moles of to moles of 
using the molar ratio. ( 1 mol = 1 mol of ).</u>
3) <u>Convert from moles of to grams of using the molar mass. (100 g/mol).</u>
Finally, we can calculate the yield percent:
I hope it helps!
The representation is showing potassium atom (K) and Chlorine atom (Cl) when it ought to show their ions i.e potassium ion (K⁺) and Chlorine ion (Cl¯)
<h3>Dissociation equation for KCl</h3>
When potassium chloride, KCl dissolves in water, it dissociate to produce potassium ion (K⁺) and Chlorine ion (Cl¯) as shown below:
KCl(aq) —> K⁺(aq) + Cl¯(aq)
The representation given in the question is only showing potassium atom (K) and Chlorine atom (Cl). This makes it wrong as dissolution of ionic compounds in water will results in the corresponding ions of the element that makes up the compound
Please see attached photo
Learn more about dissociation equation:
brainly.com/question/25854432
The empirical formula is SCl_2.
The <em>empirical formula</em> (EF) is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the <em>molar ratio </em>of S to Cl.
Assume that you have 100 g of sample.
Then it contains 31.14 g S and 68.86 g Cl.
<em>Step</em> 1. Calculate the <em>moles of each element</em>
Moles of S = 31.14 g S × (1 mol S/(32.06 g S) = 0.971 30 mol S
Moles of Cl = 68.86 g Cl × (1 mol Cl/35.45 g Cl) = 1.9425 mol Cl
<em>Step 2</em>. Calculate the <em>molar ratio</em> of each element
Divide each number by the smallest number of moles and round off to an integer
S:Cl = 0.971 30: 1.9425 = 1:1.9998 ≈ 1:2
<em>Step 3</em>: Write the <em>empirical formula</em>
EF = SCl_2
