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lisov135 [29]
4 years ago
7

Please help me with these asap!

Chemistry
1 answer:
Oksanka [162]4 years ago
8 0

Answer: okay this should get you started

Explanation:

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Please help it’s a test due in five minutes! I’ll give 10 points
barxatty [35]

Answer: negative acellaration or mass.

Explanation:

the first reason why is that i got that quistion right. and when objects are unbalanced it gives negative acellaration

3 0
3 years ago
When solid ammonium chloride dissociates at a certain temperature in a 0.500 dm3 container, ammonia and hydrogen chloride are fo
SIZIF [17.4K]
1) Reaction

<span>NH4Cl(s) ---> NH3(g) + HCl(g)


2) equilibrium equation, Kc


Kc = [NH3] * [HCl]


3) Table of equilibrium formation



step               concentrations
                       </span>
<span>                            NH4Cl(s)                     NH3(g)             HCl(g)


start                      1.000 mole                     0                    0


react                        - x


produce                                                       +x                  + x
                         ------------------                ----------              -----------

end                         1 - x                             +x                    +x
            

1 - x = 0.3 => x = 1 - 0.3 = 0.7


[NH3] = [HCl] = 0.7/0.5 liter = 1.4                (I used 0.500 dm^3 = 0.5 liter)


4) Equilibrium equation:


Kc = [NH3] [HCl] = (1.4)^2  = 1.96


Which is the number that you were looking for.


Answer: Kc = 1.96
</span>
8 0
4 years ago
If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (205)
tiny-mole [99]

Answer:

204.73K

Explanation:

the formula : PV=nRT

n=4

P=5.6 atm

V=12 L

R=0.08206 L atm mol-1 K-1

T=?

So, if you plug it in, you will get:-

T=PV/nR

T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)

T=204.73 K

hope this is correct!

4 0
3 years ago
Describe, in detail, how to make 5.5 liters of a 2.5 molar HCl solution from a 10.5 molar HCl stock solution.
Misha Larkins [42]
The stock solution contains 10.5 moles of HCl per litre. A 5.5 litre solution of 2.5M HCl contains 5.5x2.5 = 13.75moles of HCl. Since every litre of stock solution provides 10.5M HCl, the amount of stock solution needed is 13.75/10.5 = 1.309L. Therefore you would dilute 1.309L of stock solution to 5.5L
5 0
3 years ago
In order to become stable, Potassium, K, will _______ and have a resulting charge of _____.
svlad2 [7]

Answer:

D

Explanation:

it doesn't matter how many protons k has all the answers have electron with the positive charge when is negative the question is trying to distract you D is the only one that would use the electrons sign correctly

4 0
3 years ago
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