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OlgaM077 [116]
3 years ago
15

(S)-3-Methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane as the major product. Is the

product chiral
Chemistry
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

No, the product is not chiral

Explanation:

The compound (S)-3-Methylhexane is chiral. However, the bromination of this compound via free radical mechanism yields an achiral intermediate as shown in the image attached to this answer.

This achiral intermediate is a flat and planar tertiary radical. Attack on either face of this radical specie is possible. This leads us to obtain a 50-50 mixture of (R) and (S) - 3-bromo-3-methylhexane.

This is a racemic mixture hence it is optically inactive.

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what is the percent yield of NaCl if 31.0 g of CuCl reacts with excess NaNo3 to produce 21.2 g of NaCl
olchik [2.2K]
Percentage Yield = (Actual Yield ÷ Theoretical Yield) × 100  

The Actual Yield is given in the question as 21.2 g of NaCl.  However, in order to find the theoretical yield, you have to write a balanced equation and use the mole ratio to calculate the mass of NaCl that would be produced.

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Moles of CuCl = Mass of CuCl ÷ Molar Mass of CuCl
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Now, Mass of NaCl = Moles of NaCl × Molar Mass of NaCl
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