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3 years ago

Someone pls help me I will make you brain

Chemistry

1 answer:

Andreyy893 years ago

6 0

c- i and iii

I hope this helps

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What is the weight on earth of a book with a mass of 1.5kg

Marta_Voda [28]

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One peanut M&M weighs approximately 2.33 g.

Sphinxa [80]

Answer:

There are 23076 peanut M&M's in 53.768 kg of M&M's.

Explanation:

First we convert 53.768 kg into g:

53.768 kg * 1000 = 53768 g

Then we divide the total mass of M&M's by the mass of one peanut M&M, in order to calculate the answer:

53768 g / 2.33 g = 23076

So there are 23076 peanut M&M's in 53.768 kg of M&M's.

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If a sodium atom looses an electron to form an ion what is its charge?

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Help me plz I don’t know what it’s mean

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1 has the highest density because it has the most amount of circles in the least amount of space- it is the most densely filled with circles; it is the most dense.

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3 years ago

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1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.

Anarel [89]

Answer: The temperature of the system is 273 K

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of carbon dioxide = 1 lb = 453.6 g (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

$\text{Moles of carbon dioxide}=\frac{453.6g}{44g/mol}=10.31mol$

To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm (Conversion factor: 1 psia = 0.068 atm)

V = Volume of carbon dioxide = $0.6ft^3=16.992L$ (Conversion factor: $1ft^3=28.32L$ )

n = number of moles of carbon dioxide = 10.31 mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the system = ?

Putting values in above equation, we get:

$13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K$

Hence, the temperature of the system is 273 K

8 0

3 years ago