The <span>graph of y = 3/(4x-12) is decreasing sloping to the right mostly in the third quadrant whereas the graph of y = 1/x is like a mirror that is present in both quadrant 1 and 2.</span>
I dont know the answer
Step-by-step explanation:
little girl I am sorry
Answer:
x=0 and y=2
Step-by-step explanation:
We have been given system of equations:
2x+5y=10 (1)
And 2x+3y=6 (2)
Subtract equation (2) from(1) we get:
2y=4
y=2
Now, substitute y=2 in equation(2) we get:
2x+3(2)=6
2x+6=6
2x=0
x=0
Hence, x=0 and y=2
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
PQ // BC
then
Angle P = Angle B, A is common angle the two triangles are similar
AP/AB = AQ/AC
8/18 = 12/ AC
AC = 12 * 18/8 = 27 (your ans: D)
AQ + QC = AC
QC = AC - AQ = 27 - 12 = 15 (if it was required)
tan60 = y/8
y = s tan60 = 8sqrt(3) (B)
Next time, post each question separately.
