Answer:
see explanation
Step-by-step explanation:
(5)
Using the trigonometric identity
sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x
Given
3sin²Θ + 2cos²Θ - 2
= 3sin²Θ + 2(1 - sin²Θ) - 2
= 3sin²Θ + 2 - 2sin²Θ - 2
= sin²Θ
(6)
Using the trigonometric identity
secx = 
Consider the left side
= 
= = secx = right side ⇒ verified
(7)
Using the trigonometric identity
1 + cot²x = csc²x
Given
sin²x. cot²x + sin²x ← factor out sin²x from each term
= sin²x(cot²x + 1)
= sin²x. csc²x
= sin²x × 
= 1
Starting with a different number changes the diagram because if you started with any other number, you would get different results.
Answer:
α = 62°
β = 56°
gamma = 90°
Step-by-step explanation:
ΔAOB is isosceles, so m∠A = m∠ABO = 28
28 + 28 + m∠AOB = 180
m∠AOB = 180 - 28 - 28 = 124
β = 180 - 124 = 56
arcAB = 124
ΔBOC is isosceles. α = m∠BCO = 1/2(arc AB) = 1/2(124) = 62
∠D is inscribed in a semicircle
m∠D = gamma = 90°
Answer:
(x + 9)(x4)
Step-by-step explanation:
So, the possible side
lengths of the quilt are (x + 9) and (x + 4) units.
A) There was no change in the number of students on honor roll from one year to the next. This is noticeable because 200/1000 = .2 just as 20%/100% = .2 or 20/100 = .2. So there never was a change!
