The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
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6.25 is the answer to the problem
Answer:
length x width x height and 25
Answer:
y
=
3
2
x
+
1
Explanation:
To find the slope
(
m
)
of the straight line that passes through two points
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
apply:
(
y
1
−
y
2
)
=
m
(
x
1
−
x
2
)
In this example our two points are
(
0
,
1
)
and
(
2
,
4
)
Hence:
(
1
−
4
)
=
m
(
0
−
2
)
−
3
=
−
2
m
→
m
=
3
2
The equation of a straight line in slope
(
m
)
and intercept
(
c
)
form is:
y
=
m
x
+
c
In this example:
y
=
3
2
x
+
c
Since the point
(
0
,
1
)
is on this line
→
1
=
0
+
c
Hence,
c
=
1
∴
y
=
3
2
x
+
1
is our required straight line.
Step-by-step explanation:
Answer:
Dh
Step-by-step explanation:
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