Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Answer:
answer 11
Step-by-step explanation:
I think it the right answer
Answer:
The correct answer is option D: 
Step-by-step explanation:
Given:
log(y)= 3.994
Solution:
A logarithm base b of a positive number x satisfies the following definition:

For 
Also if no base b is indicated, the base of the logarithm is assumed to be 10
.
Thus, in log(y)= 3.994 base b is not indicated. so its base is assumed to be 10
now

Then

Answer:
14
Step-by-step explanation:
im different
Answer:
.03 cents
Step-by-step explanation:
6 divided by 200 equals 0.03