3 years ago

How could I track my running speed without a car or special equipment?

Physics

2 answers:

xeze [42]3 years ago

5 0

You could be counting while running

WARRIOR [948]3 years ago

5 0

Answer:

hi there! remember me? please mark my ans as the brainliest buddy!

Explanation:

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salantis [7]

Answer: inertia

Explanation:

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3 years ago

A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber

Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

$V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}$

Now calculate the bouyant force acting on the lead

$F_L = Vpg$

$F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N$

This force will act in upward direction

Gravitational force on the lead due to its mass will act in downward direction

Hence the difference of this two force

$T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N$

If V is the volume submerged in the water then bouyant force on the bobber is

$F_B=V'pg$

Equate bouyant force with the tension and gravitational force

$F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}$

Now Total volume of bobble is

$\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\$

= $\large\boxed{4.52 \%}$

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3 years ago

HELP Giving all the points I can. Physics virtual lab report: circuit design<br><br> Please help me.

mafiozo [28]

Answer:text me I can help

Explanation:

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4 years ago

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tekilochka [14]

Answer:

waving

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it waves go to a beach and see water doesn't rest it waves

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Young's interference experiment demonstrated the particle nature of light T/F?

MAVERICK [17]

I think the answer is false

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3 years ago